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Misha Larkins [42]
3 years ago
5

If each vitamin has 0.8 grams of calcium, how much calcium will 2.6 vitamins have?

Chemistry
1 answer:
alexandr402 [8]3 years ago
4 0
2.6 vitamins will have 2.08 calcium 
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Explanation:

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Which statement best describes the structure of covalent network solids? A. They are giant structures held together by weak forc
konstantin123 [22]

Answer: Option (B) is the correct answer.

Explanation:

A covalent compound is a compound formed by sharing of electrons. And, in a covalent network solid atoms are bonded by covalent bonds in a continuous network that is extending throughout the material or solid.

This continuous arrangement of atoms are like a lattice.

For example, diamond is a covalent network solid in which carbon atoms are arranged in a continuous lattice like structure.

Hence, we can conclude that the statement all the atoms are covalently bonded to other atoms to form a lattice-like structure, best describes the structure of covalent network solids.

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2 years ago
The adult blue whale has a lung capacity 5.0\times10^3 5.0 Ã 10 3 l. calculate the mass of air (assume an average molar mass of
Andre45 [30]
For this item, we need to assume that air behaves like that of an ideal gas. Ideal gases follow the ideal gas law which can be written as follow,
    PV = nRT
where P is the pressure, 
V is the volume,
 n is the number of mols,
R is the universal gas constant, and 
T is temperature

In this item, we are to determine first the number of moles, n. We derive the equation,
       n = PV /RT
Substitute the given values,

    n = (1 atm)(5 x 10³ L) / (0.0821 L.atm/mol.K)(0 + 273.15)
    n = 223.08 mols

From the given molar mass, we calculate for the mass of air.
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<em>ANSWER: 6464.9 g</em>
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3 years ago
Li + HNO3 &gt; LiNO3 + H2 how do I balance it? Show work pls
azamat

Answer: The balanced equation is 2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}.

Explanation:

The given reaction equation is as follows.

Li + HNO_{3} \rightarrow LiNO_{3} + H_{2}

Number of atoms present on reactant side are as follows.

  • Li = 1
  • H = 1
  • NO_{3} = 1

Number of atoms present on product side are as follows.

  • Li = 1
  • H = 2
  • NO_{3} = 1

To balance this equation, multiply Li by 2 and HNO_{3} by 2 on reactant side. Also, multiply LiNO_{3} by 2 on product side.

Hence, the equation can be rewritten as follows.

2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}

Now, number of atoms present on reactant side are as follows.

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  • H = 2
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Number of atoms present on product side are as follows.

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  • H = 2
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As there are same number of atoms on both reactant and product side. Hence, the equation is now balanced.

Thus, we can conclude that the balanced equation is 2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}.

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GarryVolchara [31]

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