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3 years ago

The high level of pollution in earth's is a planet problem

Chemistry

1 answer:

svet-max [94.6K]3 years ago

3 0

Answer:

According to the World Economic Forum, air pollution was found to be the largest current environmental threat to our public health. Up to 52,000 people die every year in the United States alone because of exposure to emissions from power plant emissions.

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A gas mixture is composed of three different gases. The first gas in the mixture has a pressure of 0.35 atm. The second gas in t

riadik2000 [5.3K]

Answer:

1.20atm

Explanation:

Given parameters:

Partial pressure of gas 1 = 0.35atm

Partial pressure of gas 2 = 0.20atm

Partial pressure of gas 3 = 0.65atm

Unknown:

Total pressure of the gas mixture = ?

Solution:

To solve this problem, we need to recall and understand the Dalton's law of partial pressure.

Dalton's law of partial pressure states that "the total pressure of a mixture of gases is equal to the sum of the partial pressure of the constituent gases".

Total pressure =Pressure of gas(1 + 2 + 3)

The partial pressure is the pressure a gas would exert if it alone occupied the volume of the gas mixture.

Now we substitute;

Total pressure = (0.35 + 0.20 + 0.65)atm = 1.20atm

8 0

3 years ago

A pH -solution is more acidic than one with pH 6 by a factor of (a) 4000 (b) 2 (c) 10000 (d) 8000

jonny [76]

the correct option is c ) 10,000...
an acid which is more acidic than 6 pH will be of pH 5 acid because if one acid is stronger than the other acid than its magnitude of strength is 1000... it is constant always...

3 0

2 years ago

Read 2 more answers

An electron in the hydrogen atom makes a transition from an energy state of principal quantum number ni to the n = 2 state. If t

topjm [15]

Answer:

$\boxed{3}$

Explanation:

The Rydberg equation gives the wavelength λ for the transitions:

$\dfrac{1}{\lambda} = R \left ( \dfrac{1}{n_{i}^{2}} - \dfrac{1}{n_{f}^{2}} \right )$

where

R= the Rydberg constant (1.0974 ×10⁷ m⁻¹) and

$\text{$n_{i}$ and $n_{f}$ are the numbers of the energy levels}$

Data:

$n_{f} = 2$

λ = 657 nm

Calculation:

$\begin{array}{rcl}\dfrac{1}{657 \times 10^{-9}} & = & 1.0974 \times 10^{7}\left ( \dfrac{1}{2^{2}} - \dfrac{1}{n_{f}^{2}} \right )\\\\1.522 \times 10^{6} &= &1.0974\times10^{7}\left(\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \right )\\\\0.1387 & = &\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \\\\-0.1113 & = & -\dfrac{1}{n_{f}^{2}} \\\\n_{f}^{2} & = & \dfrac{1}{0.1113}\\\\n_{f}^{2} & = & 8.98\\n_{f} & = & 2.997 \approx \mathbf{3}\\\end{array}\\\text{The value of $n_{i}$ is }\boxed{\mathbf{3}}$

7 0

3 years ago

A total of 5 mol iron oxide has a mass of (798.5g)

Anit [1.1K]

Answer:

Yes , 5 mole of Iron Oxide has mass of 798.5 g

Explanation:

Formula of iron oxide:

$Fe_{2}O_{3}$

Atomic mass of Fe = 55.84 amu

Atomic mass of O = 15.99 amu

Molar mass of Fe2O3 = 2(atomic mass of Fe) + 3(atomic mass of O)

= 2(55.84) + 3(15.99)

=111.68 + 47.97

= 159.69 g/mol

Molar mass always equal to 1 mole of the substance.

1 mole = 159.69 g

5 mole =

$=5\times159.69$

= 798.45 g

6 0

3 years ago

When 24g of magnesium metal is heated in air, 40g of magnesium oxide is produced. What mass of magnesium would be needed in orde

inysia [295]

Answer: 6.1 g

Explanation:

between Mg and MgO theres a 1;1 MOLE RATIO

here's the balanced equation

2Mg + O2 ==> 2MgO

24g of magnesium is approximately 1 mole of magnesium so it produces 40 g of mgo which is also 1 mole of mgo thus 10/40 =0.25 moles of MgO so 0.25 moles of magnesium would be needed which is approximately 6.1 g

6 0

3 years ago