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3 years ago

What is the product of a rational number with its reciprocal is always _________.

Mathematics

2 answers:

ra1l [238]3 years ago

6 0

Answer:

Step-by-step explanation:

Ive had this question i said 10 but the correction says its one

GIVE ME BRAINLIEST BC I KNOW IM RIGHT

tester [92]3 years ago

5 0

Answer:

hopes it helps

Step-by-step explanation:

◆ The product of a rational number with its reciprocal is always _____

Answer = 1 (one)

For example:-

Rational number be = 6/7

Reciprocal of the rational number be = 7/6

Product of both =6/7×7/6 = 1

Answer = 1

Cool isn't it?

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Can anyone help me on solving equations with rational numbers?

dangina [55]

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3 years ago

Chandra has $36.25 in dimes and quarters If she has 250 coins in total, hwo many

vladimir2022 [97]

Answer:

175 dimes and 75 quarters

Step-by-step explanation:

Make a system of equations, where d is the number of dimes and q is the number of quarters:

d + q = 250

0.1d + 0.25q = 36.25

Solve by elimination by multiplying the top equation by -0.1:

-0.1d - 0.1q = -25

0.1d + 0.25q = 36.25

0.15q = 11.25

q = 75

Then, plug in 75 as q into one of the equations to solve for d:

d + q = 250

d + 75 = 250

d = 175

So, there are 175 dimes and 75 quarters

7 0

3 years ago

Read 2 more answers

Please help me with this question<br><br><br><br> pls, I really need help

Inessa [10]

Answer: x=7, y=-23
(7,-23)

Explanation:

4 0

2 years ago

Given that the points (-3, 2) and (1, 2) are vertices of a rectangle, what two sets of coordinates could form the other two vert

Lesechka [4]

Answer:

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3 years ago

Q6: Which is the graph of the polar equation r=1/1-sin theta.

AveGali [126]

Answer:

The correct answer is C.

Step-by-step explanation:

The given equation is;

$r=\frac{1}{1-\sin(\theta)}$

This implies that;

$r(1-\sin(\theta)=1$

$r-r\sin(\theta)=1$

Let us write in Cartesian coordinates by substituting;

$r=\sqrt{x^2+y^2} ,y=r\sin(\theta)$

$\sqrt{x^2+y^2}-y=1$

$\sqrt{x^2+y^2}=y+1$

Square both sides;

$(\sqrt{x^2+y^2})^2=(y+1)^2$

This implies that;

$x^2+y^2=y^2+2y+1$

$x^2=2y+1$

$y=\frac{1}{2}x^2-\frac{1}{2}$

This is an equation of a parabola that opens upwards with a y-intercept of $-\frac{1}{2}$ .

The correct choice is C

4 0

3 years ago