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1 year ago

What is the mean absolute deviation of 8,1,3,3,9,6

Mathematics

1 answer:

Gennadij [26K]1 year ago

6 0

Answer:

Step-by-step explanation:

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Can some explian this?

KiRa [710]

Answer: it’s asking where do the points meet at hopes this helps

Step-by-step explanation:

8 0

2 years ago

Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.

Leni [432]

Answer: $\dfrac{2x^2-1}{x(x^2-1)}$

Step-by-step explanation:

The given function : $y=\ln(x(x^2 - 1)^{\frac{1}{2}})$

$\Rightarrow\ y=\ln x+\ln (x^2-1)^{\frac{1}{2}}$ [ $\because \ln(ab)=\ln a +\ln b$ ]

$\Rightarrow y=\ln x+\dfrac{1}{2}\ln (x^2-1)}$ [ $\because \ln(a)^n=n\ln a$ ]

Now , Differentiate both sides with respect to x , we will get

$\dfrac{dy}{dx}=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})\dfrac{d}{dx}(x^2-1)$ (By Chain rule)

[Note : $\dfrac{d}{dx}(\ln x)=\dfrac{1}{x}$ ]

$\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x-0)$

[ $\because \dfrac{d}{dx}(x^n)=nx^{n-1}$ ]

$=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x) = \dfrac{1}{x}+\dfrac{x}{x^2-1}\\\\\\=\dfrac{(x^2-1)+(x^2)}{x(x^2-1)}\\\\\\=\dfrac{2x^2-1}{x(x^2-1)}$

Hence, the derivative of the given function is $\dfrac{2x^2-1}{x(x^2-1)}$ .

8 0

3 years ago

Morgan rewrote the expression 90 + (10 + 4.8) as (90 + 10) + 4.8. How will this change the work that is needed to evaluate the e

serg [7]

Answer:

Answer is c

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Help asap!!! Please help

Pie

Why dont you try B.33

4 0

2 years ago

Read 2 more answers

Somebody please help me idk what to do ‍♂️‍♂️

Arte-miy333 [17]

Answer:

Step-by-step explanation:

Note that n! = n(n - 1)(n - 2) ..... × 3 × 2 × 1, thus

7! = 7 × 6 × 5 × 4 × 3 × 2 × 1

5! = 5 × 4 × 3 × 2 × 1

2! = 2 × 1

Hence

cancel 5 × 4 × 3 × 2 × 1 on numerator/ denominator, leaving

$\frac{7(6)}{2(1)}$ = $\frac{42}{2}$ = 21

8 0

3 years ago