Answer:
<h2>12) There are 534 students who do not lunch in school.</h2>
Step-by-step explanation:
<h3>12. </h3><h3>Simple solution: </h3><h3>890 ÷ 5 = 178 </h3><h3>Therefore: 1/5 = 178 </h3><h3 /><h3>•To find the 2/5 of the students, we have to multiply 178 by 2</h3><h3>178 × 2 = 356</h3><h3>Therefore, 356 students stay to have lunch.</h3><h3 /><h3>•To find the remaining students who do not lunch in school, we have to subtract 356 to 890.</h3><h3>890 - 356 = 534</h3><h3>Therefore, there are 534 students who do not lunch in school.</h3><h3 /><h3 />
Answer:
1/4
Step-by-step explanation:
1st: you need to make a common denominator for 2/3 and 11/12 that would be 12, so you would keep 11/12 how it is but multiply the numerator and the denominator by 4 to get it to 12.
You would have ;
8/12+___=11/12
Then just do 11/12-8/12
so that would simplify out to 1/4
Volume of a triangular pyramid is v=1/3AH so the answer is 8
Answer:
Supplementary
Step-by-step explanation:
84 plus 96 equals 180 degrees
supplementary angles are angles that add up to 180 so their relationship is supplementary
Answer:
Minimum value of function
is 63 occurs at point (3,6).
Step-by-step explanation:
To minimize :

Subject to constraints:

Eq (1) is in blue in figure attached and region satisfying (1) is on left of blue line
Eq (2) is in green in figure attached and region satisfying (2) is below the green line
Considering
, corresponding coordinates point to draw line are (0,9) and (9,0).
Eq (3) makes line in orange in figure attached and region satisfying (3) is above the orange line
Feasible region is in triangle ABC with common points A(0,9), B(3,9) and C(3,6)
Now calculate the value of function to be minimized at each of these points.

at A(0,9)

at B(3,9)

at C(3,6)

Minimum value of function
is 63 occurs at point C (3,6).