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jek_recluse [69]
3 years ago
12

Mackenzie has d dimes and a quarters. She has a minimum of $3 worth of coins altogether. Write this situation as an inequality.

Mathematics
2 answers:
uysha [10]3 years ago
4 0

Good evening

Vedmedyk [2.9K]3 years ago
3 0

Answer:

Step-by-step explanation:

d = dimes and a = quarters

0.10d + 0.25a > = 3 (thats greater then or equal) <===

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Given f(x) = -x – 2, find f (3).
damaskus [11]
To solve this, plug 3 into x. The equation will be f(3)=-3-2. This simplifies to -5.
6 0
3 years ago
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Solve x/9 + 1/3 = -4/3<br> The solution is x = ?
nydimaria [60]

Answer:

x = - 15

Step-by-step explanation:

\frac{x}{9} + \frac{1}{3} = - \frac{4}{3} ( multiply through by 9 to clear the fractions )

x + 3 = - 12 ( subtract 3 from both sides )

x = - 15

6 0
2 years ago
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MAVERICK [17]
It Would Be B   x+3/x-3



4 0
3 years ago
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1/3(6x-15)=1/2(10x-4) solve for x
Tatiana [17]

Simplify 1/3(6x - 15) to 6x - 15/3

6x - 15/3 = 1/2(10x - 4)

Factor out the common term; 3

3(2x - 5)/3 = 1/2(10x - 4)

Cancel out 3

2x - 5 = 1/2(10x - 4)

Simplify 1/2(10x - 4) to 10x - 4/2

2x - 5 = 10x - 4/2

Factor out the common term; 2

2x - 5 = 2(5x - 2)/2

Cancel out 2

2x - 5 = 5x - 2

Subtract 2x from both sides

-5 = 5x - 2 - 2x

Simplify 5x - 2 - 2x to 3x - 2

-5 = 3x - 2

Add 2 to both sides

-5 + 2 = 3x

Simplify -5 + 2 to -3

-3 = 3x

Divide both sides by 3

- 1 = x

Switch sides

<u>x = -1</u>

8 0
3 years ago
Why is the equation y-y1=m(x-x1) called the point-slope form?
MatroZZZ [7]

Answer:

The equation of the line with slope m = 2 and passing through the point (1, 1) will be:

y = 2x

Step-by-step explanation:

We know that the point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

The formula y-y_1=m\left(x-x_1\right) is termed as the point-slope form of the line equation because if we know one point on a certain line and the slope of that line, then we can easily get the line equation with this formula and, hence, determine all other points on the line.

For example, if we are given the point (1, 1) and slope m = 2

Then substituting the values m = 2 and the point (1, 2)

y-y_1=m\left(x-x_1\right)

y - 2 = 2(x-1)

y - 2 = 2x-2

y = 2x-2+2

y = 2x

Therefore, the equation of the line with slope m = 2 and passing through the point (1, 1) will be:

y = 2x

5 0
2 years ago
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