(xy)' + (2x)' + (3x^2)' = (4)'
y + xy' + 2 + 6x = 0
xy' = -y -2 -6x
y' = [-y -2 -6x] / x
Now solve y from the original equation and substitue
xy + 2x + 3x^2 = 4 => y = [-2x - 3x^2 + 4] / x
y' = [(-2x - 3x^2 +4) / x - 2 - 6x ] / x
y' = [-2x - 3x^2 + 4 -2x -6x^2 ] x^2 = [ -4x - 9x^2 + 4] / x^2 =
= [-9x^2 - 4x + 4] / x^2
Y-3=-4(x-10)
Add 3 to make it go to the right side.
y=-4(x-10)+3
From here, you have the answer.
You change the sign for the 10 because it is in parentheses.
So, it is (10,3), or B.
Answer:
<em>It must have 4 roots</em>
Step-by-step explanation:
<u>Fundamental Theorem of Algebra</u>
One polynomial of degree n will have exactly n roots. The degree of a polynomial is the highest exponent of its variable. Some of the roots could be real, some could be imaginary (complex). If n is odd, at least one of the roots is real.
The polynomial given in the question is
has a degree of 4 (the highest exponent of x). According to the Fundamental Theorem of Algebra, it must have 4 roots
The Gauss-Jordan elimination method different from the Gaussian elimination method in that unlike the Gauss-Jordan approach, which reduces the matrix to a diagonal matrix, the Gauss elimination method reduces the matrix to an upper-triangular matrix.
<h3>
What is the Gauss-Jordan elimination method?</h3>
Gauss-Jordan Elimination is a technique that may be used to discover the inverse of any invertible matrix as well as to resolve systems of linear equations.
It is based on the following three basic row operations that one may apply to a matrix: Two of the rows should be switched around. Multiply a nonzero scalar by one of the rows.
Learn more about Gauss-Jordan elimination method:
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