3 years ago

PROBABILITIES!!!!!!!!!!!

Mathematics

1 answer:

Dima020 [189]3 years ago

6 0

$|\Omega|=8\\|A|=6\\\\P(A)=\dfrac{6}{8}=0.75$

You might be interested in

Write the expressions as an equivalent power with a negative exponent. 1/49 and 27/125

hoa [83]

$n^{-x}=\frac1{n^x}$

$\textcircled1\ \frac1{49}=\frac1{7^2}=\boxed{7^{-2}}$

$\textcircled2\ \frac{27}{125}=\frac{3^3}{5^3}=(\frac35)^3=\frac1{(\frac{5}{3})^3}=\boxed{\left(\frac53\right)^{-3}}$

7 0

3 years ago

A conditional linear equation has how many solutions?

Jobisdone [24]

Answer:

If solving a linear equation leads to a single solution such as x = 3, the equation is conditional. Its solution set consists of a single element.

4 0

2 years ago

Find the difference: 2x + 10 - 3 / x+4

mash [69]

Sn you are going to be

5 0

3 years ago

Solve for y Just ignore this - hhjjjxmznfncnf f cucbc

Gnom [1K]

Answer:

Step-by-step explanation:

y/7.5=11/10

y=7.5(11)/10

y=8.25mm

3 0

3 years ago

: If tan A=- 9/13 and 0 < A < 180, find, without using tables or calculators, the value of

stich3 [128]

Answer: $\bold{\sin A=\dfrac{9\sqrt{10}}{50}\qquad \cos A=-\dfrac{13\sqrt{10}}{50}}$

Step-by-step explanation:

0° < A < 180° so it is in Quadrant I or II

since tan A is negative, it is in Quadrant II ---> (-x, +y)

$\text{Given}:\tan A=\dfrac{y}{x}\ =\dfrac{9}{-13}$

Next, find the hypotenuse given that x = -13 and y = 9

(-13)² + (9)² = r²

250 = r²

5√10 = r

$\sin A = \dfrac{y}{r}\quad =\dfrac{9}{5\sqrt{10}}\bigg(\dfrac{\sqrt{10}}{\sqrt{10}}\bigg)\quad =\large\boxed{\dfrac{9\sqrt{10}}{50}}\\\\\\\\\cos A = \dfrac{x}{r}\quad =\dfrac{-13}{5\sqrt{10}}\bigg(\dfrac{\sqrt{10}}{\sqrt{10}}\bigg)\quad =\large\boxed{-\dfrac{13\sqrt{10}}{50}}$

8 0

3 years ago