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3 years ago

This chapter discusses that light sometimes acts like a photon. What is a photon?

Physics

1 answer:

Deffense [45]3 years ago

8 0

Answer:

c. a self-contained "packet" of electro-magnetic energy

Explanation:

Photon is a quantum of energy packet of electromagnetic radiation, it contains all the properties of electromagnetic radiation being the fundamental component of electromagnetic energy.

It behaves like a wave when it propagates in a medium but transfers energy like a particle when collides with some other matter.

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Suppose the sun were to suddenly disappear. what would happen to the orbital path of earth? it would stay the same, but the eart

Vilka [71]

C: It would follow a path perpendicular to the radius of its current orbit

When there is nothing to keep it going in circles, it will stop moving in circles around the sun and continue in a straight path. Think of it as a catapult. If the stick stops, the rock keeps flying straight at the speed and direction it was flung.

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3 years ago

Read 2 more answers

uppose one gallon of gasoline produces 1.17×108 J of energy, and this energy is sufficient to operate a car for 18.3 miles. An a

EleoNora [17]

Answer:

4.5 x 10^6 miles

Calculations can be viewed on the snapshot attached to this reply.

Thanks

8 0

4 years ago

the musical note A above middle C has a frequency of 440 Hz. If the speed of the sound is known to be 350 m/s, what is the wavel

Leona [35]

Wavelength = speed / frequency

= (350 m/s) / (440/s)

=. 0.795 meter

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3 years ago

Read 2 more answers

May you help me answer this

Firdavs [7]

1) See three Kepler laws below

2a) Acceleration is $2.2 m/s^2$

2b) Tension in the string: 27.4 N

3a) Kinetic energy is the energy of motion, potential energy is the energy due to the position

3b) The kinetic energy of the object is 2.25 J

Explanation:

There are three Kepler's law of planetary motion:

1st law: the planets orbit the sun in elliptical orbits, with the Sun located at one of the 2 focii
2nd law: a segment connecting the Sun with each planet sweeps out equal areas in equal time intervals. A direct consequence of this is that, when a planet is further from the sun, it travels slower, and when it is closer to the sun, it travels faster
3rd law: the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit. Mathematically, $T^2 \propto r^3$ , where T is the period of revolution and r is the semi-major axis of the orbit

2a)

To solve the problem, we have to write the equation of motions for each block along the direction parallel to the incline.

For the block on the right, we have:

$M g sin \theta - T = Ma$ (1)

where

$Mg sin \theta$ is the component of the weight of the block parallel to the incline, with

M = 8.0 kg (mass of the block)

$g=9.8 m/s^2$ (acceleration of gravity)

$\theta=35^{\circ}$

T = tension in the string

a = acceleration of the block

For the block on the left, we have similarly

$T-mg sin \theta = ma$ (2)

where

m = 3.5 kg (mass of the block)

$\theta=35^{\circ}$

From (2) we get

$T=mg sin \theta + ma$

Substituting into (1),

$M g sin \theta - mg sin \theta - ma = Ma$

Solving for a,

$a=\frac{M-m}{M+m}g sin \theta=\frac{8.0-3.5}{8.0+3.5}(9.8)(sin 35^{\circ})=2.2 m/s^2$

2b)

The tension in the string can be calculated using the equation

$T=mg sin \theta + ma$

where

m = 3.5 kg (mass of lighter block)

$g=9.8 m/s^2$

$\theta=35^{\circ}$

$a=2.2 m/s^2$ (acceleration found in part 2)

Substituting,

$T=(3.5)(9.8)(sin 35^{\circ}) +(3.5)(2.2)=27.4 N$

3a)

The kinetic energy of an object is the energy due to its motion. It is calculated as

$K=\frac{1}{2}mv^2$

where

m is the mass of the object

v is its speed

The potential energy is the energy possessed by an object due to its position in a gravitational field. For an object near the Earth's surface, it is given by

$U=mgh$