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padilas [110]
3 years ago
7

This chapter discusses that light sometimes acts like a photon. What is a photon?

Physics
1 answer:
Deffense [45]3 years ago
8 0

Answer:

c. a self-contained "packet" of electro-magnetic energy

Explanation:

Photon is a quantum of energy packet of electromagnetic radiation, it contains all the properties of electromagnetic radiation being the fundamental component of electromagnetic energy.  

It behaves like a wave when it propagates in a medium but transfers energy like a particle when collides with some other matter.

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A purse at radius 2.00 m and a wallet at radius 3.00 m travel in uniform circular motion on the floor of a merry-go-round as the
djverab [1.8K]

Complete Question:

A purse at radius 2.00 m and a wallet at radius 3.00 m travel in uniform circular motion on the floor of a merry-go-round as the ride turns.

They are on the same radial line. At one instant, the acceleration of the purse is (2.00 m/s2 ) i + (4.00 m/s2 ) j .At that instant and in unit-vector notation, what is the acceleration of the wallet

Answer:

aw = 3 i + 6 j m/s2

Explanation:

  • Since both objects travel in uniform circular motion, the only acceleration that they suffer is the centripetal one, that keeps them rotating.
  • It can be showed that the centripetal acceleration is directly proportional to the square of the angular velocity, as follows:

       a_{c} = \omega^{2} * r (1)

  • Since both objects are located on the same radial line, and they travel in uniform circular motion, by definition of angular velocity, both have the same angular velocity ω.

       ∴ ωp = ωw (2)

           ⇒ a_{p} = \omega_{p} ^{2} * r_{p} (3)

               a_{w} = \omega_{w}^{2} * r_{w} (4)

  • Dividing (4) by (3), from (2), we have:

        \frac{a_{w} }{a_{p}} = \frac{r_{w} }{r_{p}}

  • Solving for aw, we get:

        a_{w} = a_{p} *\frac{r_{w} }{r_{p} } = (2.0 i + 4.0 j) m/s2 * 1.5 = 3 i +6j m/s2

7 0
3 years ago
a student lift a 25kg mass at vertical distance of 1.6m in a time of 2.0 seconds. a. Find the force needed to lift the mass (in
zhannawk [14.2K]

Answer:

a. F = 245 Newton.

b. Workdone = 392 Joules.

c. Power = 196 Watts

Explanation:

Given the following data;

Mass = 25kg

Distance = 1.6m

Time = 2secs

a. To find the force needed to lift the mass (in N );

Force = mass * acceleration

We know that acceleration due to gravity is equal to 9.8

F = 25*9.8

F = 245N

b. To find the work done by the student (in J);

Workdone = force * distance

Workdone = 245 * 1.6

Workdone = 392 Joules.

c. To find the power exerted by the student (in W);

Power = workdone/time

Power = 392/2

Power = 196 Watts.

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3 years ago
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How long would it take for a sound impulse to travel through an aluminum rod 1,500 meters long?
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