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padilas [110]
4 years ago
7

This chapter discusses that light sometimes acts like a photon. What is a photon?

Physics
1 answer:
Deffense [45]4 years ago
8 0

Answer:

c. a self-contained "packet" of electro-magnetic energy

Explanation:

Photon is a quantum of energy packet of electromagnetic radiation, it contains all the properties of electromagnetic radiation being the fundamental component of electromagnetic energy.  

It behaves like a wave when it propagates in a medium but transfers energy like a particle when collides with some other matter.

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Compare and contrast the lithosphere and the asthenosphere(3 different 2 similarities)
worty [1.4K]
Before comparing and contrasting these layers of Earth, we first define what lithosphere and asthenosphere are. 

Lithosphere primarily consists of the outermost layers of the Earth, which are the crust and the uppermost portion of the mantle. Simply, the ground you stepped on is part of earth's lithosphere. On the other hand, asthenosphere comprises of hot and partially molten rock just located at the upper portion of the mantle but just below the lithosphere. Both have similarities and differences, which are as follows:

SIMILARITIES:
- Both are the passageways of earthquakes P-waves (Primary waves) just before it reaches the earth's surface.
- Both are made of the same material (Silicon oxide rocks, which are rich in iron and magnesium)

DIFFERENCES:
- Rocks in lithosphere can bend (it deforms, resulting in fault formations), however, rocks in the asthenosphere, not only bend but also flow (plastic in nature).
- Lithosphere has relatively low temperatures compared to asthenosphere.
- Due to its depth, pressure against rocks in asthenosphere is comparatively higher compared to lithosphere.

8 0
3 years ago
A 3.50-meter length of wire with a cross-sectional area of 3.14 × 10-6 meter2 is at 20° Celsius. If the wire has a resistance of
maks197457 [2]

Answer:

5.6\times 10^{-8}\ Ohm.m

Explanation:

Resistivity is given by \rho=\frac {AR}{L} where A is cross-sectional area, R is resistance, L is the length and \rho is the reistivity. Substituting 0.0625 for R, 3.14 × 10-6 for A and 3.5 m for L then the resistivity is equivalent to

\rho=\frac {3.14\times 10^{-6}\times 0.0625}{3.5}=5.60714285714285714285714285714285714285\times 10^{-8}\approx 5.6\times 10^{-8}\ Ohm.m

8 0
4 years ago
1. What happens in the process of radioactive decay? What is the half-life of a radioactive substance, and how is it used to dat
Ierofanga [76]
<span> In radioactive decay, an unstable atomic nucleus emits particles or radiation and converts to a different atomic nucleus. If the new nucleus is unstable, it will decay again, until eventually, a stable nucleus is formed. Such a sequence of nuclear decays forms a decay series.

The half-life of a radioactive substance is the time required for half of the atoms of a radioactive isotope to decay. If you have, say, 1 million atoms of a specific isotope in a sample, the time required for 500,000 of those atoms to decay is the half-life of that specific isotope. If you have 50 atoms of that isotope, 25 atoms will decay in the same amount of time.

Because the half-life is fixed for a specific isotope, it can be used to date objects. You compare the decay rate of an old object with the decay rate of a fresh sample. Nuclear decay is a first-order process and can be described by a specific mathematical equation, which depends on the decay rate and the half-life. Knowing those values, you can work back and determine the age of an object, as compared with a standard sample. Old objects will not have as much of a radioactive isotope in them as new objects, since the isotopes will have decayed over time in the old object.</span>
6 0
4 years ago
3. Predict which of the following ions would be likely to form: _____ a. Na2+ _____ b. Cl+ _____ c. Ca2+ _____ d. Br– _____ e. N
Over [174]
The answer is : <span> Ca2+ & </span><span> Br. 
Na2 would not give away 2 electrons.
Cl would not give away any electron
Ne- & Ne+ are noble gases, so, they do not give up or take electrons.</span>
6 0
3 years ago
Read 2 more answers
Use the information below for the next five questions:
sergey [27]

Answer:  Please see answer in explanation column.

Explanation:

Given that

v≈(331 + 0.60T)m/s

where Temperature, T =  14°C

v≈(331 + 0.60 x 14)m/s

v =331+ 8.4 = 339.4m/s

In our solvings, note that

f= frequency

 λ=wavelength

L = length

v= speed of sound

a) Length of the pipe is calculated using the fundamental frequency formulae that

f=v/2L

Length = v/ 2f

= 339.4m/s/ 2 x 494Hz ( s^-1)= 0.3435m

b) wavelength of the fundamental standing wave in the pipe

L = nλ/2,

λ = 2L/ n

λ( wavelength )= 2 x 0.3435/ 1

= 0.687m

c) frequency of the fundamental standing wave in the pipe

F = v/  λ

= 339.4m/s/0.687m=

494.03s^-1 = 494 Hz

d) the frequency in the traveling sound wave produced in the outside air.

This is the same as the frequency in the open organ pipe = 494Hz

e)The wavelength of the travelling sound wave produced in the outside air is the same as the wavelength calculated in b above = 0.687m

f) To play D above middle c . the distance is given by

L =v/ 2 f

= 343/ 2 x 294

=0.583m

7 0
4 years ago
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