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3 years ago

14

Monochromatic light is incident on a metal surface and electrons are ejected. If the intensity of the light is increased, what w

ill happen to the ejection rate and maximum energy of the electrons

1 answer:

MAVERICK [17]3 years ago

6 0

Answer:

<u>Increase the rate and the same maximum energy of the electrons</u>

Explanation:

According to the photoelectric effect we can say:

The number of electrons, or the electric current, has a linear behaviour with the intensity of the light and a constant behaviour whit the frequency. <u>Therefore, the rate of electrons increases.</u>

The kinetic energy of the ejected electrons has a linear dependence on the frequency of the light and has a constant behaviour with the intensity. <u>So, we can say there is the same maximum energy.</u>

<u></u>

I hope it helps you!

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A room has dimensions 3.00 m (height) 3.70 m 4.30 m. A fly starting at one corner flies around, ending up at the diagonally oppo

horrorfan [7]

The displacement is the straight-line distance it flew when everything is over. We don't count all of the turns that it made in the displacement. So if it's in an opposite corner we just need to know how far it is from one corner of a box to the opposite corner with the given dimensions. We use the Pythagorean Theorem for part a):
$d= \sqrt{3.00^{2}+3.70^{2}+4.30^{2}}=6.42m$
b). Since the displacement is the straight line path, there are no shorter paths that this.
c)All other paths are greater
d) if the fly flies this path, then they would be equal
in cartesian coordinates, the vector is the sum of the 3 components whose magnitudes are the wall lengths and whose directions are parallel to that wall:
$D=a_x3.70+a_y4.30+a_z3.00$

The shortest walking path is 7.96m.

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3 years ago

What gravitational force does the moon produce

saul85 [17]

Answer:

$1.94\cdot 10^{20} N$

Explanation:

The magnitude of the gravitational force between two objects is given by the equation:

$F=G\frac{m_1 m_2}{r^2}$

where

G is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between the objects

The gravitational force is always attractive.

In this problem, we have:

$m_1 = 5.98\cdot 10^{24}kg$ is the mass of the Earth

$m_2 = 7.34\cdot 10^{22} kg$ is the mass of the Moon

$r=3.88\cdot 10^8 m$ is the separation between the Earth and the Moon

Therefore, the gravitational force between them is

$F=(6.67\cdot 10^{-11})\frac{(5.98\cdot 10^{24})(7.34\cdot 10^{22})}{(3.88\cdot 10^8)^2}=1.94\cdot 10^{20} N$

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3 years ago

Please Help Quick ASAP Hurry This is Physical Science

krok68 [10]

Answer:

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Explanation:

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3 years ago

An object of mass 2.0 kg is attached to the top of a vertical spring that is anchored to the floor. The unstressed length of the

poizon [28]

Answer:

The value is $A = 0.014 \ m$

Explanation:

From the question we are told that

The mass of the object is $m = 2.0 \ kg$

The unstressed length of the string is $l = 0.08 \ m$

The length of the spring when it is at equilibrium is $l_e = 5.9 \ cm = 0.059 \ m$

The initial speed (maximum speed)of the spring when given a downward blow $v = 0.30 \ m/s$

Generally the maximum speed of the spring is mathematically represented as

$u = A * w$

Here A is maximum height above the floor (i.e the maximum amplitude)

and $w$ is the angular frequency which is mathematically represented as

$w = \sqrt{\frac{k}{m} }$

So

$u = A * \sqrt{\frac{k}{m} }$

=> $A = u * \sqrt{\frac{m}{k} }$

Gnerally the length of the compression(Here an assumption that the spring was compressed to the ground by the hammer is made) by the hammer is mathematically represented as

$b = l -l_e$

=> $b = 0.08 - 0.05 9$

=> $b = 0.021 \ m$

Generally at equilibrium position the net force acting on the spring is

$k * b - mg = 0$

=> $k * 0.021 - 2 * 9.8 = 0$

=> $k = 933 \ N/m$

So

$A = 0.30 * \sqrt{\frac{2}{933} }$

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3 years ago

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valkas [14]

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3 years ago