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Oksi-84 [34.3K]
3 years ago
12

Planet, , galaxy, universe. What is missing in the ordered sequence of the cosmos? A. Sun, B. Earth, C. Nebulae, D. Solar system

,
Physics
2 answers:
Artemon [7]3 years ago
8 0
D; solar system, because the planets are inside it.
Julli [10]3 years ago
3 0
Solar system because the planets are in the solar system.

                                                            
                                             :)

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The burning of 1.0 g of coal produces 35 000 joules of energy. How many kcals are produced?
sergeinik [125]
I got the 1.0g of coal producves 35,000 joules which is also 8.36 kcals
8 0
3 years ago
The law of conservation of matter states that during a chemical reaction
Sveta_85 [38]
This law states that, despite chemical reactions or physical transformations, mass is conserved — that is, it cannot be created or destroyed — within an isolated system
4 0
3 years ago
A porter can carry 40 bricks of 10 N load of each. He can carry up to 75m in 40 sec, calculate his power.​
alexira [117]

Answer:

750W

Explanation:

40×10= 400N

work done= force × distance

=400 × 75

=30000 J

Power= work done/ time

= 30000 ÷ 40

= 750 W

4 0
1 year ago
Using this information...
Pepsi [2]

19.2\:\text{m/s}

Explanation:

At the top of the tree, the velocity of the pebble is purely horizontal so we can calculate it as

v_{y} = v_{0y} = v_0\cos 40° = (25\:\text{m/s})(0.766)

\:\:\:\:\:= 19.2\:\text{m/s}

6 0
3 years ago
During an adiabatic process an object does 100 J of work and its temperature decreases by 5 K. During another process it does 25
Liono4ka [1.6K]

Answer:

The heat capacity for the second process is 15 J/K.

Explanation:

Given that,

Work = 100 J

Change temperature = 5 k

For adiabatic process,

The heat energy always same.

dQ=0

dU=-dW

We need to calculate the number of moles and specific heat

Using formula of heat

dU=nC_{v}dT

nC_{v}=\dfrac{dU}{dT}

Put the value into the formula

nC_{v}=\dfrac{-100}{5}

nC_{v}=-20\ J/K

We need to calculate the heat

Using formula of heat

dQ=nC_{v}(dT_{1})+dW_{1}

Put the value into the formula

dQ=-20\times5+25

dQ=-75\ J

We need to calculate the heat capacity for the second process

Using formula of heat

dQ=nC_{v}(dT_{1})

Put the value into the formula

-75=nC_{v}\times(-5)

nC_{v}=\dfrac{-75}{-5}

nC_{v}=15\ J/K

Hence, The heat capacity for the second process is 15 J/K.

5 0
3 years ago
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