A kilogram of silver contains 5.58×10²⁴ atoms.
<h3>How to determine the parameter</h3>
From the question given above, the following data were obtained:
- 1 mole of silver = 107.9 g
- Number of atoms in 1 mole of silver = 6.02×10²³ atoms.
- Number of atoms in a kilogram of silver is unknown
Now, we shall convert 1 kg of silver to grams (g).
This can be obtained as follow:
1 kg = 1000g
Therefore, 1 kg of silver is equivalent to 1000g.
Now, let's determine the number of atoms in 1 kg (i.e 1000 g) of silver as follow:
If 107.9 g of silver contains 6.02×10²³ atoms.
Then, 1000 g of silver will contain:
= (1000 × 6.02×10²³) / 107.9
= 5.58×10²⁴ atoms.
Thus, a kilogram of silver contains 5.58×10²⁴ atoms.
Learn more about atoms here:
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Answer:
$11
Step-by-step explanation:
Set up the system of equations
18x + 9y = 45
20x + 12y = 52
Let's try to get y on one side for the first equation.
9y=45-18x
y=5-2x
Now substitute it into the second equation.
20x + 12(5-2x) = 52
20x + 60 - 24x = 52
-4x = -8
x = 2
Now solve for y using the first equation.
18(2) + 9y = 45
36 + 9y = 45
9y = 9
y = 1
Now that we know x and y we can solve for the price of 4 hot dogs and 3 drinks.
4(2) + 3(1) = z
8 + 3 = z
11 = z
That means that the price is 11 dollars.
Can you show me the diagram
Hope it helps to solve it
Three hundred four million, Eight hundred thousand Four hundred
and standard form is the way you wrote it, 304,800,400
