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3 years ago

Unit rate of 25 meters in 2sec??

1 answer:

5 0

$\frac{25m}{2sec} \times \frac {x}{1sec}$
Crossmultiply to solve for x:
$x=\frac{25m \times 1sec}{2sec}$
$x=\frac{25}{2}m/s = 12.5m/s$

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Help me please I beg if you can

Virty [35]

Answer: The mean is 3780

Step-by-step explanation:

Mean is found by adding all values and dividing the sum by how many values were added.

4250+4019+3895+3739+3401+3376=22680
22680/6=3780

6 0

3 years ago

Let x denote the lifetime of a mcchine component with an exponential distribution. The mean time for the component failure is 25

aliina [53]

Answer:

0.1353 = 13.53% probability that the lifetime exceeds the mean time by more than 1 standard deviations

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

The mean time for the component failure is 2500 hours.

This means that $m = \frac{2500}, \mu = \frac{1}{2500} = 0.0004$

What is the probability that the lifetime exceeds the mean time by more than 1 standard deviations?

The standard deviation of the exponential distribution is the same as the mean, so this is P(X > 5000).

$P(X > x) = e^{-0.0004*5000} = 0.1353$

0.1353 = 13.53% probability that the lifetime exceeds the mean time by more than 1 standard deviations

4 0

2 years ago

The cost of a car rental is $30 per day plus 18c per mile. You are on a daily budget of $75. Write and solve an inequality to

Tanzania [10]

Answer:

2. 5 miles

Step-by-step explanation:

Given that:

Rental cost = $30

Cost per mile driven = 18 cent

Daily budget = $75

Greatest distance you can drive each day while staying within budget :

Rental cost + (cost per mile driven * distance) ≤ daily budget

$30 + 18d ≤ $75

18d ≤ 75 - 30

18d ≤ 45

d ≤ 45 / 18

d ≤ 2.5

Greatest distance you can drive each day while staying within budget is 2.5 miles.

8 0

3 years ago

Simplify 4ab - 6a^2b + 3ab^2 +3b - 6qb

Diano4ka-milaya [45]

3 0

3 years ago

Addy has 51.79 pounds of dirt. She has buckets in her garage. Each bucket can hold 2.5 pounds of dirt. If she has 20 buckets wil

kirill [66]

Answer:

Step-by-step explanation:

20x2.5=50

51.79-50=1.79

therefore there isn't enough buckets for all the dirt.

4 0

3 years ago

Read 2 more answers