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kirill [66]
2 years ago
10

QUESTION 2

Mathematics
1 answer:
tangare [24]2 years ago
3 0
It’s c!!!!!!!!!!!!! !
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AB has endpoints at (-4,5) and (4,-3) using the midpoint formula what is the midpoint segment
Mamont248 [21]

Answer:

(0,1)

Step-by-step explanation:

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3 years ago
Factorisation of 4x^2-5x-1
max2010maxim [7]
I am not sure but it is right if your question is right.

3 0
2 years ago
D<br> Evaluate<br> arcsin<br> (6)]<br> at x = 4.<br> dx
sineoko [7]

Answer:

\frac{1}{2\sqrt{5} }

Step-by-step explanation:

Let, \text{sin}^{-1}(\frac{x}{6}) = y

sin(y) = \frac{x}{6}

\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})

\frac{d}{dx}\text{sin(y)}=\frac{1}{6}

\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx} ---------(1)

\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}

\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}

cos(y) = \sqrt{1-\text{sin}^{2}(y) }

          = \sqrt{1-(\frac{x}{6})^2}

          = \sqrt{1-(\frac{x^2}{36})}

Therefore, from equation (1),

\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}

Or \frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}

At x = 4,

\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}

\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}

                   =\frac{1}{6\sqrt{\frac{36-16}{36}}}

                   =\frac{1}{6\sqrt{\frac{20}{36} }}

                   =\frac{1}{\sqrt{20}}

                   =\frac{1}{2\sqrt{5}}

4 0
3 years ago
Function help please
Korvikt [17]

Answer:

The first table represents a function.

Step-by-step explanation:

For it to be a function, there needs to be 1 unique y value of 1 unique x value.

  • Looking at 2nd table, we see x value of -5 is mapped to 2 different y values of -5 and 5. So this is not a function.
  • Looking at 3rd table, we see x value of -2 is mapped to 2 different y values of 2 and 4. So this is not a function.
  • Looking at 4th table, we see x value of -4 is mapped to 2 different y values of 2 and 0. So this is not a function as well.

Looking at table 1, there are no duplicate x values and each of the 4 x values map to different values. So the first table represents a function.

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3 years ago
-(2x + y) +3 (x - 4y)
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X-13y is the answer to that equation
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