Answer:
E)The gravitational force increases by a factor of 4.
Explanation:
Isaac Newton presented the law of Universal Gravitation in his book published in 1687, "Philosophiae Naturalis Principia Mathematica". According to this Newton's law, the more mass the objects possess, the greater the force of attraction, and the closer they are to each other, the greater that force will be.
All material particles and all bodies attract each other simply by having mass, in direct proportion to their masses.<u> Gravity has an infinite theoretical scope; but, the force is greater if the objects are close, and while they are moving away that force loses intensity in proportion to the square of the distance that separates the bodies</u>. For example, if one object moves away from another three times the distance, then the force of gravity is reduced to the ninth part or vice versa if the distance between objects decreases with a factor of 2, the gravitational force increases a factor of 4.
Newton's law of universal gravitation is expressed as follows
:
Fg = G * M1 * M2 / (r12)^2
Where:
Fg: gravitational force
G: it is the universal gravitation constant and is worth approximately 6,674 * 10 -11
M1 and M2: mass of objects
r12: distance between objects
Answer:
t = 125 C
Explanation:
The force on a charge due to other charge is given by Coulomb's Law, as follows:
F = kq₁q₂/r²
where,
F = Electric Force = 5 N
k = Coulomb Constant = 9 x 10⁹ N.m²/C²
q₁ = magnitude of first charge = 15 nC = 1.5 x 10⁻⁸ C
q₂ = Magnitude of 2nd Charge = t = ?
r = distance between charges = 15 m
Therefore,
5 N = (9 x 10⁹ N.m²/C²)(1.5 x 10⁻⁸ C)t/(15 m)²
t = (5 N)/(0.04 N/C)
<u>t = 125 C</u>
Lamina occupies x² + y² = 14y. Outside circle is x² + y² = 49
To find the mass of lamina, integrate given density function over the region
m = ∫∫D P(x, y) dA
Subtitute x = r cosФ and y = r sinФ in x² + y² = 14y
and x² + y² = 49
x² + y² = 14y
(r cosФ)² + ( rsinФ)² = 14(rsinФ)
r² = 14r sin Ф
x² +y² = 49
r² = 49
r = 7
Cntre mass (-x. -y)
-x= i/m ∫∫D xp(x,y) dA = 1/m∫∫ (r cosФ) p( r, Ф)r
dr dФ
-y = 1/m∫∫D yp(x, y) dA = 1/m ∫∫D (r sinФ) p(r, Ф) r drФ
where m = ∫∫D p(x, y) dA
12.
The twelve cranial nerves are: olfactory nerve, optic nerve, oculomotor nerve, trochlear nerve, trigeminal nerve, abducens nerve, facial nerve, vestibulocochlear nerve, glossopharengeal nerve, vagus nerve, spinal accessory nerve, and hypoglossal nerve.
:)
Answer:
100 m/s
Explanation:
We'll begin by converting 1 km to m. This can be obtained as follow:
1 km = 1000 m
Finally, we shall determine the final velocity of the car. This can be obtained as follow:
Initial velocity (u) = 0 m/s
Acceleration (a) = 5.0 m/s²
Distance (s) = 1000 m
Final velocity (v) =?
v² = u² + 2as
v² = 0² + (2 × 5 × 1000)
v² = 0 + 10000
v² = 10000
Take the square root of both side
v = √10000
v = 100 m/s
Therefore, the speed value of the car is 100 m/s.