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Elena-2011 [213]

3 years ago

9

2.when sugar or another substance is dissolved in water, it disappears from view and forms a homogeneous mixture with the water,

also called a solution. if you can’t see the sugar, how can you tell that it is there?

1 answer:

bekas [8.4K]3 years ago

3 0

You cant really tell when it is dissolved

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How to calculate motion

otez555 [7]

Answer:

Distnace per unit time

Explanation:

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3 years ago

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Vectors a and b have scalar product â6.00, and their vector product has magnitude +9.00. what is the angle between these two vec

salantis [7]

Answer:

Value of angle between vector a and b is $56.30^{\circ}$ .

Explanation:

Vectors a and b have scalar product 6.00

Let $\theta$ be the angle between a and b.

$\vec{a}.\vec{b} = 6$

ab cos $\theta$ = 6 ...(1)

Vectors a and b have magnitude of vector product 9.00

$\vec{a} \times\vec{b} = 9$

ab sin $\theta$ = 9 ...(2)

Dividing equation (2) by (1) we get

$\frac{ab sin \theta}{ab cos \theta} = \frac{9}{6}$

tan $\theta$ = 1.5

$\theta = tan ^{-1} (1.5)$

$\theta$ = $56.30^{\circ}$

Thus, value of angle between vector a and b is $56.30^{\circ}$ .

3 0

3 years ago

Question 8 (1 point)

sineoko [7]

Answer:

A

Explanation:

6 0

2 years ago

If the lily pads are spaced 2.4 m apart and Ferdinand jumps with a speed of 5 m/s taking 0.6 s to go from lily pad to lily pad,

Zina [86]

Answer:

$36.87^{\circ}$

Explanation:

v = Velocity of Ferdinand = 5 m/s

$\theta$ = Angle of jump

T = Time taken = 0.6 s

R = Distance between lily pads = 2.4 m

Horizontal range is given by

$R=v_xT\\\Rightarrow R=vcos\theta T\\\Rightarrow cos\theta=\dfrac{R}{vT}\\\Rightarrow \theta=cos^{-1}\dfrac{R}{vT}\\\Rightarrow \theta=cos^{-1}\dfrac{2.4}{5\times 0.6}\\\Rightarrow \theta=36.87^{\circ}$

The angle at which Ferdinand make each of his jumps is $36.87^{\circ}$

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3 years ago

A generator uses a coil that has 100 turns and a 0.50-T magnetic field. The frequency of this generator is 60.0 Hz, and its emf

lana [24]

Answer:

38 m

Explanation:

Number of turns=N=100

Magnetic field=B=0.50 T

Frequency of the generator=f=60 Hz

Rms value of emf= $E_{rms}=120 V$

We have to find the length of the wire from which the coil is made.

Peak value of emf= $E_0=E_{rms}\sqrt 2=120\times \sqrt 2=169.7 V$

Length of wire= $4\sqrt{\frac{NE_0}{2\pi fB}}$

Substitute the values

Length of wire= $4\times \sqrt{\frac{169.7\times 100}{0.50\times 2\pi\times 60}}$

Length of wire=38 m

Hence, the length of wire from which the coil is made=38 m

6 0

3 years ago