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Licemer1 [7]
3 years ago
15

Can someone please help me I don’t understand this

Physics
1 answer:
jolli1 [7]3 years ago
4 0
I think it’s a because it the only reasonable answer
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Which light is most sensitive to the eyes?
san4es73 [151]

Answer:

Our eyes are most sensitive to the wavelengths corresponding to the yellow and green colors of the spectrum. Flashy signs and some fire engines are painted in a yellowish-green color to attract our attention.

6 0
3 years ago
Why are hot springs and geysers is found in areas of present or a past activity
Lady_Fox [76]
<span>Hot springs and geysers are often found in areas of present or past volcanic activity. The hot spring forms when water deep underground is heated by a nearby body of magma or hot rock. The hot water rises and collects in a natural pool; when rising hot water and steam become trapped in a narrow crack, pressure builds until the mixture sprays above the surface as a geyser.</span>
7 0
3 years ago
Will Mark BRAINLIEST!!!!!!!!!!!!!!!!!!!
vazorg [7]

3.

a)

r = distance of each mass in each hand from center = 0.6 m

m = mass of each mass in each hand = 2 kg

v = linear speed = 1.1 m/s

L = combined angular momentum of the masses = ?

Combined angular momentum of the masses is given as

L = 2 m v r

L = 2 (2) (1.1) (0.6)

L = 2.64 kg m²/s


b)

v' = linear speed when she pulls her arms = ?

r' = distance of each mass from center after she pulls her arms = 0.15 m

Using conservation of momentum , angular momentum remains same, hence

L = 2 m v' r'

2.64 = 2 (2) (0.15) v'

v' = 4.4 m/s


4 0
4 years ago
A magnet in the form of a cylindrical rod has a length of 7.30 cm and a diameter of 1.5 cm. It has a uniform magnetization of 5.
yulyashka [42]

Answer:

Magnetic dipole moment is 0.0683 J/T.

Explanation:

It is given that,

Length of the rod, l = 7.3 cm = 0.073 m

Diameter of the cylinder, d = 1.5 cm = 0.015 m

Magnetization, M=5.3\times 10^3\ A/m

The dipole moment per unit volume is called the magnetization of a magnet. Mathematically, it is given by :

M=\dfrac{\mu}{V}

\mu=M\times \pi r^2\times l

Where

r is the radius of rod, r = 0.0075 m

\mu=5.3\times 10^3\ A/m\times \pi (0.0075)^2\times 0.073\ m

\mu=0.0683\ J/T

So, its magnetic dipole moment is 0.0683 J/T. Hence, this is the required solution.

6 0
3 years ago
Read 2 more answers
A force of 20 N produces an acceleration of 10 m/s² in mass m1 and an acceleration of 5 m/s² in
Scrat [10]

Explanation:

F = 20N m= m1 a=10m/s²

m=m2 a=5m/s²

F = ma

<u>for the first one</u><u>:</u><u> </u>

f=m1 × a

20 = m1 ×10

20=10m1

m1=20/10

m1=2

<u>for</u><u> </u><u>the</u><u> </u><u>second</u><u> </u><u>one</u><u> </u><u>:</u>

f=m2×a

20=m2×5

m2= 20/5

m2= 4

since F=ma

F=(m1+m2) ×a

F =(4+2)×a

F =6×a

F=20(from the question above )

20=6×a

a=20/6

a=3.33

8 0
4 years ago
Read 2 more answers
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