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Licemer1 [7]
2 years ago
15

Can someone please help me I don’t understand this

Physics
1 answer:
jolli1 [7]2 years ago
4 0
I think it’s a because it the only reasonable answer
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A jet starts at rest at the end of a runway and reaches a speed of 80 m/s in 20 s. What is its acceleration?
ahrayia [7]

Answer:

Acceleration=velocity/time.

=80/2=40m/s^2.

4 0
3 years ago
In a face, you run 3000 meters east in 21 minutes. What is your velocity in km/min?
Anni [7]

3 \times  \ 21
7 0
3 years ago
The following situation will be used for the next three problems: A rock is projected upward from the surface of the moon, at ti
chubhunter [2.5K]

Explanation:

Given that,

Initial speed of the rock, u = 30 m/s

The acceleration due to gravity at the surface of the moon is 1.62 m/s².

We need to find the time when the rock is ascending at a height of 180 m.

The rock is projected from the surface of the moon. The equation of motion in this case is given by :

h=ut-\dfrac{1}{2}gt^2\\\\180=30t-\dfrac{1}{2}\times 1.62t^2

It is a quadratic equation, after solving whose solution is given by:

t = 7.53 s

or

t = 8 seconds

(e)If it is decending, v = -20 m/s

Now t' is the time of descending. So,

v=-u+gt\\\\t=\dfrac{v+u}{g}\\\\t=\dfrac{20+30}{1.62}\\\\t=30.86\ s

Let h' is the height of the rock at this time. So,

h'=ut-\dfrac{1}{2}gt^2\\\\h'=30\times 30.86-\dfrac{1}{2}\times 1.62\times 30.86^2\\\\h'=154.40\ m

or

h' = 155 m

6 0
3 years ago
HELP <br> What is the goal of a theory?
Dafna1 [17]

Hi,

The goal of a theory is <u>to explain natural and physical </u><u>phenomena.</u>

Hope it helps you...

Pls mark brainliest if it helps you...

(Answered by Benjemin)

4 0
2 years ago
In an experiment, students measure the position x of a cart as a function of time t for a cart that starts at rest and moves wit
Minchanka [31]

Given :

Initial velocity , u = 0 m/s² .

To Find :

The acceleration of the cart.

Solution :

Since, acceleration is constant.

Using equation of motion :

x = ut + \dfrac{at^2}{2}\\\\x = \dfrac{at^2}{2}

Putting, t = 1 s  and x = 4 m in above equation, we get :

4 = \dfrac{a(1)^2}{2}\\\\a = 8 \  m/s^2

Therefore, the acceleration of the cart is 8 m/s².

5 0
3 years ago
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