A car starts from rest with an acceleration of 5.0 m / s² and travels a distance of 1.0 km. What is the speed value of this car?
1 answer:
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Refer to the diagram shown below.
The component of the applied force perpendicular to the door is
F * sin(60°) = 0.866F N
Because the moment arm is 0.40 m, the torque is
(0.866F N)*(0.4 m) = 0.3464F N-m
This torque is equal to 1.4 N-m, therefore
0.3464F = 1.4
F = 4.04 N
Answer: 4.04 N
The component of the applied force perpendicular to the door is
F * sin(60°) = 0.866F N
Because the moment arm is 0.40 m, the torque is
(0.866F N)*(0.4 m) = 0.3464F N-m
This torque is equal to 1.4 N-m, therefore
0.3464F = 1.4
F = 4.04 N
Answer: 4.04 N
Answer:
a)α= 53.13°
b)The velocity at the highest point = 15 m/s
The acceleration at the highest point = 9.8
c)h=15 m
V=18.02 m/s
Explanation:
Speed of water ,u= 25 m/s
So the horizontal component of speed u = u cos α
Given that horizontal distance cover by water in 3 s is 45 m.
So We know that in projectile motion horizontal acceleration is zero.
In horizontal direction
Distance = Velocity x time
45 = u cos α x 3
u cos α = 45
45 = 25 cos α x 3
cos α = 45/75
α= 53.13°
So the velocity at the highest point = u cos α
The velocity at the highest point = 15 m/s
The acceleration at the highest point = 9.8
Now the velocity along vertical direction(Vo) = u sin α
Vo= 25 sin 53.13°
Vo =20 m/s
h=15 m
So at 15 m above the ground water will strike .
The y-component of velocity after 3 sec
Vy= Vo - g t
Vy = 20 - 10 x 3
Vy= -10 m/s
The horizontal component of velocity will remain 15 m/s.
The resultant velocity
V=18.02 m/s