All categories

3 years ago

A car starts from rest with an acceleration of 5.0 m / s² and travels a distance of 1.0 km. What is the speed value of this car?

Physics

1 answer:

Pepsi [2]3 years ago

5 0

Answer:

100 m/s

Explanation:

We'll begin by converting 1 km to m. This can be obtained as follow:

1 km = 1000 m

Finally, we shall determine the final velocity of the car. This can be obtained as follow:

Initial velocity (u) = 0 m/s

Acceleration (a) = 5.0 m/s²

Distance (s) = 1000 m

Final velocity (v) =?

v² = u² + 2as

v² = 0² + (2 × 5 × 1000)

v² = 0 + 10000

v² = 10000

Take the square root of both side

v = √10000

v = 100 m/s

Therefore, the speed value of the car is 100 m/s.

You might be interested in

What kind of movement does the heat within the core and mantle directly generate?

cluponka [151]

Heat within the earth generates convection currents in the mantle. Convection currents represent the circular motion of molten rocks in the mantle driven by heat from the core. This circular motion is what drives the plates and creates the theory of plate tectonics which states that the earth crust is divided into plates that float on the semi-molten mantle below.

7 0

3 years ago

In what phase of matter do molecules vibrate but stay in position?

Veronika [31]

Answer:

solid

Explanation:

they molecules are closely together

5 0

4 years ago

A block of mass m moving due east at speed v collides with and sticks to a block of mass 2m that is moving at the same speed vv

lapo4ka [179]

Answer:

30.36°

Explanation:

By using linear momentum; linear momentum can be expressed by the relation:

$mv_xi + mv_yj$

where ;

m= mass

$v_x$ = velocity of components in the x direction

$v_y$ = velocity of components in the y direction

If we consider the east as the positive x and north as positive y which is synonymous to what we usually have on a graph.

Then;

Initial momentum = $mvi + 2mvcos 45i + 2mvsin45 j$

= $(mv+2mvcos45)i + (2mvsin45)j$

However, the masses stick together after collision and move with a common velocity: $V_xi +V_yj$

∴ Final momentum = $3mv (V_xi +V_yj)$

= $3mV_xi + 3mV_yj$

From the foregoing ;

initial momentum = final momentum

$3mV_xi + 3mV_yj = (mv+2mvcos45)i+(2mvsin45j)$

So;

$3mV_x = mv + 2mv cos 45 \\\\3mV_y = 2mV sin 45$

$V_x = \frac{mv+2mvcos45 }{3m}\\\\V_x = \frac{v+2vcos45}{3}$

$V_y = \frac{2mvsin45}{3m} \\\\V_y = \frac{2vsin45}{3}$

Finally;

The required angle θ = $tan^{-1} = \frac{V_y}{V_x}$

θ = $tan^{-1} = \frac{\frac{2vsin45}{3}}{\frac{v+2v.cos45}{3}}$

θ = $tan^{-1} = \frac{2sin 45}{1+2cos45}\\\\$

θ = 30.36°

7 0

3 years ago

During a breath, the average human lung expands by about 0.50 l. part a if this expansion occurs against an external pressure of

saveliy_v [14]

Work, in thermodynamics, is the amount of energy that is transferred from one system to another system without transfer of entropy. It is equal to the external pressure multiplied by the change in volume of the system. It is expressed as follows:

W = PdV

Integrating and assuming that P is not affected by changes in V or it is constant, then we will have:

W = P (V2 - V1)

Substituting the given values:
P = 1.0 atm = 101325 Pa
(V2 - V1) = 0.50 L =
W = 101325 N/m^3 ( 0.50) (1/1000) m^3
W = 50.66 N-m or 50.66 J

So, in the expansion process about 50.66 J of work is being done.

8 0

3 years ago

A 3 kg object is moving along a horizontal surface. The kinetic energy of the object is increasing at a constant rate of 6 J/m;

Whitepunk [10]

To solve this problem we will apply the concepts of energy conservation and Newton's second law that defines force as the product of the object's mass with its acceleration. Additionally we will apply concepts related to the kinematics equations of linear motion.

For conservation of energy we have that work is equal to kinetic energy therefore,

$W = KE$