The correct question is
<span>how many times as large is the approximate radius of a mercury atom, 1.50*10^-11 meter, as the approximate radius of a hydrogen atom, 2.5*10^-11
</span>
Since both are conveniently --------> *10^-11
<span>we can just divide 2.5 by 1.5
</span>2.5/1.5-------> 1.6666
<span>So a hydrogen atom is 1.67 times larger than a mercury atom</span>
45+8.3 = 53.3
<span>45 - (2(8.3)) = 28.4
The value is </span> 28.4 <span>that is –2 standard deviations away from the mean.</span><span>
</span>
Answer: Value of m = 9
Step-by-step explanation:
Given that the relationship between Q and m is;
Q = 17m
Make m the subject of formula
M = Q/17
If Q is greater than 150 and less than 160, then, let assume that
Q = 151, then
M = 151/17
M = 8.88
If Q = 159
M = 159/17
M= 9.35
Since m ranges from 8.88 to 9.35, the value of m = 9
