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Aloiza [94]
2 years ago
12

A hollow ball is made of rubber that is 2 centimeter thick. The ball has a diameter of 20 centimeters at the outside surface.

Mathematics
1 answer:
MissTica2 years ago
8 0

Answer:

628.57CM²

Step-by-step explanation:

20/2=10

VOLUME OF CYLINDER=PIR^2H

22/7*10*10*2=628.57

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After 3.5 hours, Patrick had traveled 217 miles. If he travels at a constant speed, how far will he have traveled after 4 hours
Ede4ka [16]
Answer: He would have traveled 248 miles

Explanation: This is a ratio

To find how many miles he would have traveled after 4 hours, we need to apply the information givin into a ration table

(We can put miles on the top and hours on the bottom)

217 ?
------- ------
3.5 4

Now, we can do two things:
1. cross multiply
we would take 217 times 4 (868) and divide that by 3.5 (248)

2. Divide the top and bottom by 3.5 (numerator= 62 denominator= 1)
multiply 62 by 4 to get 248

Hope this helps!


6 0
3 years ago
What's a number greater than 40 whose prime factorization contains 3 prime numbers that do not repeat
Leya [2.2K]
Well to make it easy pick 3 prime numbers. In this case I'll use 3, 11, and 13. Multiply all 3 together to get 429. For the second part, pick a prime number and multiply it by 3, in this case 3, which when multiplied by 3 equals 9. Multiply that by a prime number squared, like 11 which is 121. Then multiply by 13. 3x3x3x11x11x13 = 42471 THE CREDIT GOES TO ICEDRAPTOR
3 0
4 years ago
3. The product of 7/10 and another factor
kicyunya [14]
The correct answer is d 7/7
4 0
4 years ago
Surface area please help​
Murrr4er [49]

Answer:

238

Step-by-step explanation:

First, you have to figure out the area for each of the boxes, and then you add all of the areas together

6 0
2 years ago
A rocket is launched from the top of a 99-foot cliff with an initial velocity of 122 ft/s.
Harman [31]
Remember that c is the initial height. Since we the rocket is in a 99-foot cliff, c=99. Also, we know that the velocity of the rocket is 122 ft/s; therefore v=122
Lets replace the values into the the vertical motion formula to get:
0=-16 t^{2} +122t+99
Notice that the rocket hits the ground at the bottom of the cliff, which means that the final height is 99-foot bellow its original position; therefore, our final height will be h=-99
Lets replace this into our equation to get:
-99=-16 t^{2} +122t+99
-16 t^{2} +122+198=0

Now we can apply the quadratic formula t= \frac{-b+or- \sqrt{ b^{2} -4ac} }{2a} where a=-16, b=122, and c=198
t= \frac{-122+or- \sqrt{ 122^{2}-(4)(-16)(198) } }{(2)(-16)}
t= \frac{-122+ \sqrt{27556} }{-32} or t= \frac{-122- \sqrt{27556} }{-32}
t= \frac{-122+166}{-32} or t= \frac{-122-166}{-32}
t= \frac{-11}{8} or t=9

Since the time can't be negative, we can conclude that the rocket hits the ground after 9 seconds.
5 0
3 years ago
Read 2 more answers
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