Answer:
64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.
Step-by-step explanation:
Volume of cylinder = V
Radius of cylinder = r = 0.5 m
Height of the cylinder = 5 m
Volume of cylinder = 
Mass of gasoline = m
Density of gasoline = d = 
Work done to pump the gasoline out of the tank W
Acceleration due to gravity = g 
The center of gravity of fuel in fully filled tank will be centre so, the value of h = 2 m + 0.5 m = 2.5 m
64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.
Answer:
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Step-by-step explanation:
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Answer:
Step-by-step explanation:
The answer is D. Use the Stat and then Edit button on your TI calculator to edit the values in L1 and L2 tables. In L1 enter 0, 1, 2, 3, 4, 5 and then arrow over and enter the y values into L2 the same way. Enter the number 12, then hit enter; enter the number 14, hit enter; enter the number 15 and then hit enter, etc. Do the same for the values that are going into L1.
When that is done, hit the Stat button again and arrow down to QuadReg and hit enter. Depending upon your calculator, you may have to arrow down to "calculate" or the calculator may display the equation immediately after hitting QuadReg. Again, it all depends upon your calculator.
Answer:Add them up
Step-by-step explanation:
