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DedPeter [7]
3 years ago
12

The length of a lacrosse field is 15 yards less than twice the width, and the perimeter in 270 yards. The defensive area of the

field is 3/25 of the total field area. Find the defensive area of the lacrosse field.
Mathematics
1 answer:
sammy [17]3 years ago
5 0

The defensive area is 510 square yards

Step-by-step explanation:

Let L be the length of the rectangle

and

W be the width

According to given statement

L = 2W-15

Perimeter = 270

P = 2W+2L\\270 = 2W + 2(2W-15)\\270 = 2W + 4W -30\\270 +30 = 6W\\6W = 300

Dividing both sides by 6

\frac{6W}{6} =\frac{300}{6}\\W = 50\ yards\\\\and\\L = 2(50) -15\\= 100-15\\=85\ yards

We have to find the area first to find the defensive area

So,

Area = L* W\\= 85 * 50\\=4250\ square\ yards

Defensive area = 3/25 of total area

So,

=\frac{3}{25}*4250\\=3 *170\\=510\ square\ yards

Hence,

The defensive area is 510 square yards

Keywords: Area, Rectangle

Learn more about area at:

  • brainly.com/question/12497249
  • brainly.com/question/1238144

#LearnwithBrainly

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Naddik [55]

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<h3>What is the location  AC + CB of  AB ?</h3>

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