The first thief takes (1/2 x + 1) . What remains ? x - (1/2x + 1)
So the 2nd thief takes 2/3 of [ x - (1/2x + 1) ]
What remains ? x - 2/3 [ x - (1/2x + 1) ]
So the 3rd thief takes 2/3 of { x - 2/3 [ x - (1/2x + 1) ] } and he takes 1 more .
What remains ? x - ( 2/3 { x - 2/3 [ x - (1/2x + 1) ] } + 1 )
And that whole ugly thing is equal to ' 1 ', so you can solve it for 'x'..
The whole problem from here on is an exercise in simplifying
an expression with a bunch of 'nested' parentheses in it.
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This is a lot harder than just solving the problem with logic and
waving your hands in the air. Here's how you would do that:
Start from the end and work backwards:
-- One diamond is left.
-- Before the 3rd thief took 1 more, there were 2.
-- That was 1/3 of what was there before the 3rd man took 2/3.
So he found 6 when he arrived.
-- 6 was 1/3 of what was there before the second thief helped himself.
So there were 18 when the 2nd man arrived.
-- 18 was 1 less than what was there before the first thief took 1 extra.
So he took his 1 extra from 19.
-- 19 was the remaining after the first man took 1/2 of all on the table.
So there were 38 on the table when he arrived.
Thank you for your generous 5 points.
3 months, i just answered this same question lol.
Answer:
6 units by 12 units
Step-by-step explanation:
Since the measurements in meters are multiples of 4, it makes this problem a little easier.
First you divide 8 by 4 to get 2
Then divide 16 by 4 to get 4
After that you're going to multiply 3 units by both quotients separately.
So you multiply 3 by 2 to get 6
Then you multiply 3 by 4 to get 12
So then you end up with a 6 unit by 12 unit drawing.
It's funny because I was actually looking for the answer to this problem. Sorry I was a little late
Answer:
The mistake is adding and there is no way to solve if you have to add
Step-by-step explanation:
Answer:
B. 17.899, 18.1, 18.31, 18.879
