Given :
An expression (cos 6m)(cos 2m) .
To Find :
We need to express it in terms as sum or difference.
Solution :
We know,
cos( A + B ) = cosA cos B - sin A sin B
cos( A - B ) = cosA cos B + sin A sin B
Adding both the equations we get :
2cos A cos B = cos( A + B) + cos( A - B )
or
cos A cos B = cos( A + B) + cos( A - B )/2
Putting value of A = 6m and B = 2m in above equation, we get :
(cos 6m)(cos 2m) = cos( 6m + 2m ) + cos( 6m - 2m )/2
(cos 6m)(cos 2m) = cos(8m) + cos(4m)/2
Hence, this is the required solution.
The answer should be true
Answer:
0.219 or 21.028%
Step-by-step explanation:
0.18 are defective, so
P(x=1) = 0.18
P(x=2) = 0.18^2 = 0.0324
P(x=3) = 0.18^3 = 0.005832
P(x=4) = 0.18^4 = 0.00104976
Then add them together: 0.21928176
Answer:
An easy way to do this problem is to follow PEMDAS if you don't know what that is it is P=() E I forgot M=Mutliply D=Division A=addition S=Sabtraction
But to do this problem first do the problem in the (3/2. 1/4) I hope this helps please reward brainlist.
