Answer:
VB = 19.9 [m/s]
Explanation:
In order to solve these problems, we must use the principle of energy conservation. Which tells us that the energy between two points after an instant of time must be equal. This is we have two points A & B, in point A is the highest point while Point B is the lowest
Now we need to identify the types of energy at each point.
<u>For point A</u>
At this point we have two energies, the kinetic energy since the roller coaster moves at a speed of 2 [m/s], in the same way there is potential energy since the roller coaster is 20 [m] above ground level.
<u>For point B</u>
At Point B we only have kinetic energy, since it is located at zero meters with respect to the ground. In this way we can determine the velocity at this point.
And the energy is expressed by means of the following expression:
where:
m = mass = 5 [kg]
VA = velocity of the roller coaster in point A = 2[m/s]
hA = elevation of the roller coaster = 20 [m]
vB = velocity of the roller coaster in point B [m/s]
Now replacing:
There are 5 dwarf plabets
The compound name for box 1 should be sodium chloride.
The type of bond for box 3 should be covalent.
The answer for you question would be : Soprano
One of the type of voice that could produce a pitch that has a speed of 343 m/s and a wavelength of 0.68 m would be soprano
hope this helps
As per the question the volume of mercury is given as 0.002 m^3 at 20 degree Celsius.
We are asked to calculate the volume of the mercury at 50 degree Celsius.
This problem is based on thermal expansion of matter.
Let us consider the initial and final volume of the mercury is denoted as -
Let the initial and final temperature of the mercury is denoted as -
As per question
The change in temperature is
Mercury is a fluid.So we have to apply volume expansion of liquid .
The coefficient of of volume expansion of mercury at 20 degree Celsius is 0.00018 per centigrade.
As per volume expansion of liquid,
Here is the volume at T degree Celsius.
Hence volume at 50 degree Celsius is calculated as-
[ans]
As per the options given in the question ,option A is close to the calculated value. So option A is right.