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Kay [80]
2 years ago
11

If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20°C, what will be the volume at 50°C?

Physics
2 answers:
mel-nik [20]2 years ago
5 0

As per the question the volume of mercury  is given as 0.002 m^3 at 20 degree Celsius.

We are asked to calculate the volume of the mercury at 50 degree Celsius.

This problem is based on thermal expansion of matter.

Let us consider the initial and final volume of the mercury is denoted as -

                                  v_{1} \ and\ v_{2}

Let the initial and final temperature of the mercury is denoted as -

                                                                    T_{1}\ and \ T_{2}

As per question

v_{1} =0.002 m^3                v_{2} =?

T_{1} =20^0 C                      T_{2} =50^0 C

The change in temperature is

                                             T_{2} -T_{1}

                                         = 50^0 C -20^0 C

                                               = 30^0 C

Mercury is a fluid.So we have to apply volume expansion of liquid .

The coefficient of of volume expansion of mercury [ \gamma ] at 20 degree Celsius is 0.00018 per centigrade.

As per volume expansion of liquid,

                                       V_{T} = v_{1} [1 +\gamma [T_{2} -T_{1} ]]

Here V_{T} is the volume at T degree Celsius.

Hence volume at 50 degree Celsius is calculated as-

                               v_{2} =v_{1} [1+\gamma[50-30]]

                                       = 0.002[1+0.00018*30]

                                       =0.0020108m^3  [ans]

As per the options given in the question ,option A is close to the calculated value. So option A is right.


kogti [31]2 years ago
5 0
<span>The answer to this question lies in understanding the Combined Gas Law in chemistry, which combines Boyle's, Charles', and Gay-Lussac's gas laws. This law shows the relationship between pressure, volume, and temperature of gases and is represented by the equation P1V1/T1 = P2V2/T2. Changes in pressure (P) and volume (V) are directly proportional to one another, but these are inversely proportional to changes in temperature (T). This question must assume that pressure is constant, so the Ps cancel out and the equation becomes V1/T1 = V2/T2. Additionally, temperature should be converted to Kelvins (K) by adding 273 to the temperature in Celsius (so 20 C = 293 K, and 50 C = 323 K). If V1 = 0.002 and T1 = 293 and T2 = 323, then we solve the equation as V2 = T2*V1/T1 or V2 = (323*0.002)/293, so the answer is approximately equal to 0.0022... or answer (C).</span>
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Light from a 560 nm monochromatic source is incident upon the surface of fused quartz (n=1. 56) at an angle of 60°. what is the
ankoles [38]

The angle of reflection is "60°".

Here we apply the law of the concept of reflection then we get the final answer easily.

The angle of incident = angle of reflection

Then, the Angle of the incident =60°

What is reflection?

  • Reflection is the phenomenon of light rays returning to the source after striking an obstruction.
  • It resembles the way a ball bounces when we toss it on a hard surface.
  • Some of the light rays that strike an item are reflected, some of them travel through it, and the remainder are absorbed by the object.
  • The given values are:Light from a monochromatic source,= 560 nm
  • The angle of incidence,= 60°
  • The surface of fused quartz (n),= 1.56
  • When a light ray does exist on a flat surface, the law or idea of reflection should apply since it includes both the reflected and "normal" light rays at the mirror surface.
  • According to the above law,Angle of incident = angle of reflection
  • Then, Angle of incident =60°.

To learn more about reflection visit: brainly.com/question/15487308

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7 0
1 year ago
An object begins x=75.2 m and undergoes a displacement of -48.7 m. what is its final position?
xz_007 [3.2K]

Answer:

26.5 m

Explanation:

x_{o} = initial position of the object = 75.2 m

x  = final position of the object

d  = displacement of the object = - 48.7  

Displacement of the object is given as the difference of final and initial position of the object

d = x - x_{o}

Inserting the values

- 48.7 = x - 75.2

x = 26.5 m

8 0
2 years ago
You are on a new planet, and are trying to use a simple pendulum to find the gravity experienced on this new planet. You find th
levacccp [35]

To solve this problem it is necessary to apply the concepts related to the Period based on the length of its rope and gravity, mathematically it can be expressed as

T= 2\pi \sqrt{\frac{L}{g}}

g = Gravity

L = Length

T = Period

Re-arrange to find the gravity we have

g = \frac{4\pi^2 L}{T^2}

Our values are given as

L = 0.35m\\T = 2s\\

Replacing we have

g = \frac{4\pi^2 L}{T^2}

g = \frac{4\pi^2 0.35}{2^2}

g = 3.45 m/s^2

Therefore the correct answer is C.

4 0
3 years ago
You test a moon buggy on Earth. When the buggy hits a bump, it oscillates up and down on its springs with a period of 4 seconds.
Blizzard [7]

Answer:

Remains same

Explanation:

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Time period of oscillation is given as

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