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den301095 [7]
3 years ago
5

A pump is partially submerged in oil and is supported by 4 springs. The oil has a specific gravity of 0.90, the weight of the pu

mp is 14.6 lb, and the submerged volume is 40 in3. What force is needed in the springs so that the pump will remain in static equilibrium
Physics
1 answer:
muminat3 years ago
7 0

Answer:

Explanation:

submerged volume of pump = 40 x 12⁻³ ft³

density of oil = .9 x 62.4 lb ft⁻³ ( specific gravity x density of water )

mass of displaced oil = 40 x 12⁻³ x  .9 x 62.4 lb

= 1.3 lb

buoyant force = 1.3 lb

weight of pump = 14.6 lb

extra force needed for balancing pump by spring

= 14.6 - 1.3

= 13.3 lb .

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The objects listed are placed at the top of a ramp and roll down to the bottom without slipping. Assuming that there is no air r
Thepotemich [5.8K]

Explanation:

For each object, the initial potential energy is converted to rotational energy and translational energy:

PE = RE + KE

mgh = ½ Iω² + ½ mv²

For the marble (a solid sphere), I = ⅖ mr².

For the basketball (a hollow sphere), I = ⅔ mr².

For the manhole cover (a solid cylinder), I = ½ mr².

For the wedding ring (a hollow cylinder), I = mr².

If we say k is the coefficient in each case:

mgh = ½ (kmr²) ω² + ½ mv²

For rolling without slipping, ωr = v:

mgh = ½ kmv² + ½ mv²

gh = ½ kv² + ½ v²

2gh = (k + 1) v²

v² = 2gh / (k + 1)

The smaller the value of k, the higher the velocity.  Therefore:

marble > manhole cover > basketball > wedding ring

7 0
3 years ago
when two object P and Q are supplied with the same quantity of heat, the temperature change in P is observed to be twice that of
Ahat [919]

<h2>When two object P and Q are supplied with the same quantity of heat, the temperature change in P is observed to be twice that of Q. The mass of P is half that of Q. The ratio of the specific heat capacity of P to Q​</h2>

Explanation:

Specific heat capacity

It is defined as amount of heat required to raise the temperature of a substance by one degree celsius .

It is given as :

Heat absorbed = mass of substance x specific heat capacity x rise in temperature

or ,

Q= m x c x t

In above question , it is given :

For Q

mass of Q = m

Temperature changed =T₂/2

Heat supplied = x

Q= mc t

or

X=m x C₁ X T₁

or, X =m x C₁ x T₂/2

or, C₁=X x 2 /m x T₂                                 (equation 1 )

For another quantity : P

mass of P =m/2

Temperature= T₂

Heat supplied is same that is : X

so, X= m/2 x C₂ x T₂                            

or, C₂=2X/m. T₂                                   (equation 2 )

Now taking ratio of C₂ to c₁, We have

C₂/C₁= 2X /m.T₂  /2X  /m.T₂

so, C₂/C₁= 1/1

so, the ratio is 1: 1

8 0
3 years ago
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