Answer:
Explanation:
submerged volume of pump = 40 x 12⁻³ ft³
density of oil = .9 x 62.4 lb ft⁻³ ( specific gravity x density of water )
mass of displaced oil = 40 x 12⁻³ x .9 x 62.4 lb
= 1.3 lb
buoyant force = 1.3 lb
weight of pump = 14.6 lb
extra force needed for balancing pump by spring
= 14.6 - 1.3
= 13.3 lb .
It's C. Length
Just think of a ruler. Hope I helped! :)
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20 joule is your answer
here
mass m =100kg
distance d=50m
acceleration due to gravity a =10m/s²
work =force×displacement
= ma/d=100×10/50=20joule
Answer:the answer is C
