To figure this out you can do a proportion
34 X
---- = ------
55 100
Then you would cross multiply to get
55x=3400
Next you would divide 3400/55 which would come out to be 61.8181818 which would be your percentage 61.81%
Step-by-step explanation:
2sin(x)cos(x) - sin(x) + 2cos(x)-1= 0
<=> sinx( 2cosx -1) + ( 2cosx -1) =0
<=> (sinx +1) + ( 2cosx-1)=0
<=> sinx=-1 or cosx= 1/2
+) sinx=1 => x= pi/2 + k×2pi
+)cosx=1/2 => x= pi/3+ k×2pi or x=-pi/3 + k×2pi
x€ [0,2pi] => x= pi/2, pi/3.
Probability of finding no defective bulb
=95/100*94/99....86/91
=95!/(85!) / (100!/90!)
= 110983/190120
=>
Probability of finding at least one defective bulb
=1-110983/190120
= 79137/190120
= 0.41625 (to 5 decimal places)
Http://mathsfirst.massey.ac.nz/Algebra/SystemsofLinEq/EMeth.htm this website explains it well