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Doss [256]
3 years ago
9

a 20-m ladder is leaning against the wall of a building which is 16m high.how far is the foot of the ladder to the building?​

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
7 0

Answer:

12 m

Step-by-step explanation:

This can be solved using the Pythagorean theorem

a^2 = b^2 + c^2

20^2= 16^2 + c^2

400= 256 + c^2

400-256= c^2

144 = c^2

c = √144

c= 12

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Correo electrónico Andrew tarda 720 segundos en ducharse. Pasa otros 420 segundos ¿Cuántos minutos se tarda Andrew en ducharse y
yarga [219]

Answer:Andrew tarda 19 minutos en ducharse y desayunar

Explicación paso a paso:

720 seg de ducharse + 420 segundos de su desayuno dan igual a 1140 segudnos

a este numero de segundos hay que pasarlo a minutos. El resultado es 19 minutos que son 1140 segundos

Step-by-step explanation:

4 0
3 years ago
A small appliance is regularly priced at $60. On sale
Vlad [161]
The selling price would be 30$ how I got was a divided 20 by 60 and so 20 goes into 60 3times that’s how I got 30$
4 0
3 years ago
Trigonometry
schepotkina [342]

The area of the triangle ABC is 207.5 square units.

Explanation:

The measurements of the sides of the triangle are AB=19, AC=24 and m\angle A=65^{\circ}

We need to determine the area of the triangle ABC.

<u>Area of the triangle:</u>

The area of the triangle can be determined using the formula,

{Area}=\frac{1}{2} b c \sin A

where b=19, c=24 and m\angle A=65^{\circ}

Substituting these values in the above formula, we get,

{Area}=\frac{1}{2}(19)(24)  \sin 65^{\circ}

Simplifying the values, we get,

{Area}=\frac{1}{2}(456) (0.91)

{Area}=\frac{1}{2}(414.96)

{Area}=207.48

Rounding off to the nearest tenth, we get,

{Area}=207.5

Thus, the area of the triangle ABC is 207.5 square units.

5 0
3 years ago
Read 2 more answers
Which line is most likely to have a slope of 10 ?
hodyreva [135]
The line that is most likely to have a slope of 10 is the second one down
6 0
3 years ago
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Solve in radians help plz
PIT_PIT [208]
I think we can use the identity  sin x/2  = sqrt [(1 - cos x) /2]

cos x -  sqrt3 sqrt ( 1 - cos x) /sqrt2 = 1

cos x - sqrt(3/2) sqrt(1 - cos x) = 1
sqrt(3/2)(sqrt(1 - cos x) =  cos x - 1   Squaring both sides:-
1.5 ( 1 - cos x) = cos^2 x - 2 cos x + 1

cos^2 x - 0.5 cos x - 0.5 = 0 

cos x = 1 , -0.5

giving x = 0 , 2pi, 2pi/3,  4pi/3  ( for  0  =< x <= 2pi)

because of thw square roots some of these solutions may be extraneous so we should plug these into the original equations to see if they fit.

The last 2 results dont fit so the answer is  x = 0 , 2pi Answer
5 0
3 years ago
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