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makvit [3.9K]
3 years ago
14

A ship sails 80 degrees for 120 nautical miles, then 200 degrees for 200 nautical miles. How far is it then from the starting po

int?

Mathematics
2 answers:
vladimir2022 [97]3 years ago
8 0

Answer: distance from the starting point = 191 nautical mile

Step-by-step explanation:

80 degree =  N80°E

200 degree = S 20°W

The distance from the starting point will be achieved by using cosine formula.

√(120²+220²-2×120×220cos60)

= 20√91

Distance = 190.79 miles

Please find the attached file for the figure.

Svetradugi [14.3K]3 years ago
7 0

Answer:

190.79 miles

Step-by-step explanation:

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A chalk board’s dimensions have an
Wewaii [24]

Step-by-step explanation:

5:3=35

5=35×3

5=105

5÷105=0.05

7 0
2 years ago
How many terms of the arithmetic sequence {1,22,43,64,85,…} will give a sum of 2332? Show all steps including the formulas used
MA_775_DIABLO [31]

There's a slight problem with your question, but we'll get to that...

Consecutive terms of the sequence are separated by a fixed difference of 21 (22 = 1 + 21, 43 = 22 + 21, 64 = 43 + 21, and so on), so the <em>n</em>-th term of the sequence, <em>a</em> (<em>n</em>), is given recursively by

• <em>a</em> (1) = 1

• <em>a</em> (<em>n</em>) = <em>a</em> (<em>n</em> - 1) + 21 … … … for <em>n</em> > 1

We can find the explicit rule for the sequence by iterative substitution:

<em>a</em> (2) = <em>a</em> (1) + 21

<em>a</em> (3) = <em>a</em> (2) + 21 = (<em>a</em> (1) + 21) + 21 = <em>a</em> (1) + 2×21

<em>a</em> (4) = <em>a</em> (3) + 21 = (<em>a</em> (1) + 2×21) + 21 = <em>a</em> (1) + 3×21

and so on, with the general pattern

<em>a</em> (<em>n</em>) = <em>a</em> (1) + 21 (<em>n</em> - 1) = 21<em>n</em> - 20

Now, we're told that the sum of some number <em>N</em> of terms in this sequence is 2332. In other words, the <em>N</em>-th partial sum of the sequence is

<em>a</em> (1) + <em>a</em> (2) + <em>a</em> (3) + … + <em>a</em> (<em>N</em> - 1) + <em>a</em> (<em>N</em>) = 2332

or more compactly,

\displaystyle\sum_{n=1}^N a(n) = 2332

It's important to note that <em>N</em> must be some positive integer.

Replace <em>a</em> (<em>n</em>) by the explicit rule:

\displaystyle\sum_{n=1}^N (21n-20) = 2332

Expand the sum on the left as

\displaystyle 21 \sum_{n=1}^N n-20\sum_{n=1}^N1 = 2332

and recall the formulas,

\displaystyle\sum_{k=1}^n1=\underbrace{1+1+\cdots+1}_{n\text{ times}}=n

\displaystyle\sum_{k=1}^nk=1+2+3+\cdots+n=\frac{n(n+1)}2

So the sum of the first <em>N</em> terms of <em>a</em> (<em>n</em>) is such that

21 × <em>N</em> (<em>N</em> + 1)/2 - 20<em>N</em> = 2332

Solve for <em>N</em> :

21 (<em>N</em> ² + <em>N</em>) - 40<em>N</em> = 4664

21 <em>N</em> ² - 19 <em>N</em> - 4664 = 0

Now for the problem I mentioned at the start: this polynomial has no rational roots, and instead

<em>N</em> = (19 ± √392,137)/42 ≈ -14.45 or 15.36

so there is no positive integer <em>N</em> for which the first <em>N</em> terms of the sum add up to 2332.

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3 years ago
What’s the correct answer
laila [671]
C. 502

All you need to do is multiply the number if sales by the percentage in decimal form. Using DPR I know that 11% is equal to 0.11, so 4,560(0.11) is 501.60. That can be rounded to 502 sales that were shirts.

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3 years ago
What number is 250% of 4.2?​
agasfer [191]

Answer

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Step-by-step explanation:

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How to multiply 7985 times 490 times 39 times 2094 plz the couculator wont help
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Answer:319530474900

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