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Answer:
55 sq. in.
Step-by-step explanation:
Area of figure
= area of triangle + area of rectangle
height of triangle = 6 in.
base of triangle = 6/(sqrt(3)/3) = 18/sqrt(3)
Area of triangle = 6*18/sqrt(3) /2 = 54/sqrt(3) = 31.18 sq. in.
Area of rectangle = 6 * 4 = 24 sq. in
Area of figure = 31.18+24 = 55.18 sq. in
3x-15=x+3/3
9x-45=x+3
9x-x=3+45
8x=48
x=6
∠ABC=3×6-15=3°
∠DEF=6+3/3=3°
Hope my answer helped u :)
![\bf \sqrt[3]{x^2}\implies \left(\stackrel{outer~function}{\left( \stackrel{inner~function}{x} \right) }\right)^{\frac{2}{3}}\implies \stackrel{\qquad \qquad chain~rule}{\stackrel{outer}{\cfrac{2}{3}x^{-\frac{1}{3}}}}\cdot \stackrel{inner}{1} \\\\\\ \cfrac{2}{3x^{\frac{1}{3}}}\implies \cfrac{2}{3\sqrt[3]{x}}](https://tex.z-dn.net/?f=%5Cbf%20%5Csqrt%5B3%5D%7Bx%5E2%7D%5Cimplies%20%5Cleft%28%5Cstackrel%7Bouter~function%7D%7B%5Cleft%28%20%5Cstackrel%7Binner~function%7D%7Bx%7D%20%5Cright%29%20%20%7D%5Cright%29%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%5Cimplies%20%5Cstackrel%7B%5Cqquad%20%20%5Cqquad%20%20chain~rule%7D%7B%5Cstackrel%7Bouter%7D%7B%5Ccfrac%7B2%7D%7B3%7Dx%5E%7B-%5Cfrac%7B1%7D%7B3%7D%7D%7D%7D%5Ccdot%20%5Cstackrel%7Binner%7D%7B1%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B2%7D%7B3x%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%7D%5Cimplies%20%5Ccfrac%7B2%7D%7B3%5Csqrt%5B3%5D%7Bx%7D%7D)
so, the function is really a composite function, you could think of it