3 years ago

The chess club members bought 6 tickets to a tournament for $15. How much would they have paid if all 9 members wanted to go?

1 answer:

8 0

Answer:$22.50

Step-by-step explanation:You need to divide the cost by th numbers of objects to get the answer.15 divided by 6 equals $2.50. Since each ticket costs $2.50,you multiply 2.50 times 9 which gets you $22.50.

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stich3 [128]

Answer:

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Step-by-step explanation:

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2 years ago

I have three times as many cats as Alice but Bob has 7 less cats than me. In total we have 56 cats. How many cats do I have?

Nookie1986 [14]

The number of cats that you have is; 27 cats

<h3>How to calculate algebra word problems?</h3>

Let the number of cats alice has be x.

Since you have thrice the amount of cats that alice has, then you have 3x cats.

Bob has 7 less cats than you. Thus, bob has; 3x - 7

If they have a total of 56 cats, then;

x + 3x - 7 + 3x = 56

7x - 7 = 56

7x = 56 + 7

7x = 63

x = 63/7

x = 9

Thus, number of cats you have = 3x = 3 * 9 = 27 cats

Read more on algebra word problems at; brainly.com/question/13818690

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2 years ago

4 1/2 + 1 + 2 + 1 1/4 + 1/2 + 2/4 how did you get the answer

Anestetic [448]

Your answer is 9 3/4.

6 0

2 years ago

Read 2 more answers

Solve 7 ÷ one half = ___. Question 1 options: 14 15 24 40

Norma-Jean [14]

Answer:

O 14

Step-by-step explanation:

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7 0

2 years ago

3=m/12 help asap Have a great day:)

lisov135 [29]

Answer:

3=m/12

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2 years ago