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Lera25 [3.4K]
3 years ago
13

A worker submits the following data on a timesheet: Week 1 — Total hours: 42 (including 4 hrs sick leave, 6 hrs travel) Week 2 —

Total hours: 46 (including 5 hrs travel) What percentage of the recorded time did the worker spend traveling?
Mathematics
1 answer:
Assoli18 [71]3 years ago
6 0

Answer:

12.5%

Step-by-step explanation:

In order to find the percentage the worker spent traveling, we can make us of the following ratio:

\frac{number}{ammount}=\frac{percent}{100}

where number is how many hours he spent traveling, ammount is the total ammount of hours he reported and percent is the percentage we want to find. So we can solve the ratio for the percent, so we get:

percent=\frac{number}{ammount}*100%

now, we need to find the total amount of hours he spent traveling, this is gotten by adding the provided data:

6hrs+5hrs=11hrs

next we need to find the total amount of hours reported:

42hrs+46hrs=88hrs

so now we can substitute the data the problem provided us with:

percent=\frac{11}{88}*100%

which yields:

percent=12.5%

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A batsman scored the following number of runs in six innings:
vlabodo [156]

Answer:

D

Step-by-step explanation:

The mean or average is calculated by summing each element and then dividing by the number of elements.

We have: 35, 30, 45, 65, 44, and 21.

There are six elements in total.

We find the sum by adding. Hence:

35+30+45+65+44+21=240

We will now divide by 6, the number of elements:

240/6=40

Therefore, the mean runs scored by the batsman is 40.

Hence, our answer is D.

4 0
3 years ago
What is the probability of rolling a pair of dice and getting a sum that is not 8?
storchak [24]

Answer:

1/7

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6 0
3 years ago
Simplify the expression 12k-2+6k<br><br> A. 16k2<br> B. 10k+6<br> C. 18k-2<br> D. 16k
WITCHER [35]
12k-2+6k

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C
5 0
4 years ago
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A young equestrian loved to ride her horse all day long, dreaming of the day she would ride in the Kentucky Derby. One day in ea
Vsevolod [243]
The first step is:
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Savatey [412]

Step-by-step explanation:

55 – 5q > 4(7–9)

4(-2)

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q=12.6

8 0
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