Answer A B C and D please for my chemistry hw
1 answer:
<u>Answer:</u> The equations are provided below.
<u>Explanation:</u>
Skeleton equations are defined as the equations which simply indicate the molecules that are involved in a chemical reaction. These equations are unbalanced equations.
Balanced equations are defined as the chemical equation in which number of individual atoms on the reactant side must be equal to the number of individual atoms on the product side.
- For A:
Water decomposes in the direct current to form hydrogen and oxygen.
Skeleton Equation:
Balanced Equation:
- For B:
Mercury (II) oxide decomposes in heat to form mercury, oxygen.
Skeleton Equation:
Balanced Equation:
- For C:
Calcium carbonate when heated forms calcium oxide and carbon dioxide.
Skeleton Equation:
Balanced Equation:
- For D:
Group 2 hydroxides, when heated forms oxide and water vapor.
Skeleton Equation:
Balanced Equation:
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As the temperature increases, B) the molecules started moving faster.
Explanation:
The temperature of a substance is a measure of the average kinetic energy of the particles in a substance. In particular, it can be found that the temperature is directly proportional to the average kinetic energy of the particles:
The kinetic energy of a particle is given by
where
m is the mass of the particle
v is its speed
This means that the higher the temperature of a substance, the greater the speed of the particles in the substance.
Therefore, if we apply this concept to this problem, we infer that as the temperature of the water in the pond gets higher, the speed of the molecules inside the water increases, which means that the molecules are moving faster.
Therefore, the correct answer is
B) the molecules started moving faster.
Learn more about temperature:
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This is a straightforward dilution calculation that can be done using the equation
where <em>M</em>₁ and <em>M</em>₂ are the initial and final (or undiluted and diluted) molar concentrations of the solution, respectively, and <em>V</em>₁ and <em>V</em>₂ are the initial and final (or undiluted and diluted) volumes of the solution, respectively.
Here, we have the initial concentration (<em>M</em>₁) and the initial (<em>V</em>₁) and final (<em>V</em>₂) volumes, and we want to find the final concentration (<em>M</em>₂), or the concentration of the solution after dilution. So, we can rearrange our equation to solve for <em>M</em>₂:
Substituting in our values, we get
So the concentration of the diluted solution is 0.05875 M. You can round that value if necessary according to the appropriate number of sig figs. Note that we don't have to convert our volumes from mL to L since their conversion factors would cancel out anyway; what's important is the ratio of the volumes, which would be the same whether they're presented in milliliters or liters.