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kozerog [31]
3 years ago
12

A. First: Two central carbons are bonded to C H subscript 3 above left and right, and to H below left and right. Second: Two ce

ntral carbons are bonded to H above left and below right, and C H subscript 3 above right and below left. B. 2 skeletal models. First: 3 central C atoms have C H 3 bonded at each end of the chain; C H 3 is bonded to the first of the 3, and 2, C H 3 are bonded to the third. The first and second central carbons are double bonded. Second: A chain of 3 central C’s have C H 3 bonded at each end, with C H 3 double-bonded bonded to the first of the 3, and 2, C H 3’s bonded to the third. C. 2 skeletal models: First: A 9 carbon chain, with the first two carbons double-bonded. Second: A 10 carbon chain, with the first 2 carbons double bonded. Which pairs of compounds are geometric isomers? A. B. C.
Chemistry
2 answers:
Dominik [7]3 years ago
6 0

Answer:

A & C

Explanation:

vladimir1956 [14]3 years ago
5 0

If I am correct I just got this question?

Its A

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Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb 1.30 MJ o
Sunny_sXe [5.5K]

Answer:

97 000 g Na

Explanation:

The absortion (or liberation) of energy in form of heat is expressed by:

q=m*Cp*ΔT

The information we have:

q=1.30MJ= 1.30*10^6 J

ΔT = 10.0°C = 10.0 K (ΔT is the same in °C than in K)

Cp=30.8 J/(K mol Na)

If you notice, the Cp in the question is in relation with mol of Na. Before using the q equation, we can find the Cp in relation to the grams of Na.

To do so, we use the molar mass of Na= 22.99g/mol

Cp= \frac{30.8J}{K*mol Na}*\frac{1 mol Na}{22.99 g Na}=1.34\frac{J}{K*g Na}

Now, we are able to solve for m:

m=\frac{1.30*10^6 J}{1.34\frac{J}{K*g Na} *10.0K}=\frac{1.30*10^6J}{13.4\frac{J}{g Na} }  = 9.70*10^4 g Na=97 Kg Na=97 000 g Na

7 0
3 years ago
Read 2 more answers
A flask holds 3.01 x 1023 molecules of carbon dioxide. The container is holding ________
sammy [17]
 (B), because 1.0 moles would be 6.02 x 10^23 molecules. So you have half a mole.<span>
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8 0
3 years ago
- Standard state refers to
yulyashka [42]

Answer: The standard state refers to 1 atm and 25^{o}C.

Explanation:

It is known that a chemical/substance can either be present in a solid, liquid or gaseous state.

So, when the phase of a substance like solid, liquid or gas is present at 1 atmosphere pressure and at a temperature of 25^{o}C then it known as standard state of substance.

Thus, we can conclude that standard state refers to 1 atm and 25^{o}C.

4 0
3 years ago
This is very difficult
Oliga [24]

Answer: C

Explanation:

6 0
3 years ago
Need help ASAP!<br><br> How many moles of sodium nitrate are in 0.25 L of 1.2 M NaNO3 solution?
Setler79 [48]

Answer:

\boxed {\boxed {\sf 0.3 \ mol \ NaNO_3}}

Explanation:

Molarity is a measure of concentration in moles per liter.

molarity= \frac{moles \ of \ solute}{liters \ of \ solution}

The molarity of the solution is 1.2 M NaNO₃ or 1.2 moles NaNO₃ per liter. There are 0.25 liters of the solution. The moles of solute are unknown, so we can use x.

  • molarity= 1.2 mol NaNO₃/L
  • liters of solution=0.25 L
  • moles of solute =x

1.2 \ mol \ NaNO_3/L= \frac{x}{0.25 \ L}

We are solving for x, so we must isolate the variable, x. It is being divided by 0.25 liters. The inverse of division is multiplication, so we multiply both sides by 0.25 L.

0.25 \ L *1.2 \ mol \ NaNO_3/L=\frac{x}{0.25 \ L} *0.25 \ L

0.25 \ L *1.2 \ mol \ NaNO_3/L=x

The units of liters cancel, so we are left with the units moles of sodium nitrate.

0.25  *1.2 \ mol \ NaNO_3=x

0.3 \ mol \ NaNO_3=x

There are 0.3 moles of sodium nitrate.

3 0
2 years ago
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