<u>Answer</u>
79 ml
<u>Explanation</u>
You have 237 237 ml of ammonia, whose strength is 100%.
If you want to make it 75%, then;
let 75% ⇒ 237 ml of ammonia and
25% ⇒ x ml of water.
∴ x = (25% ×237) / 75%
= 5,925/75
= 79 ml of water.
Answer:
Reaction of 1-butanol with bromobenzene
Explanation:
The reaction would yield ether as the major product is the reaction of the 1-butanol with bromobenzene. This is because the reaction does not have the large percentage of the undesired side product. In fact, the major product is about 85 % in composition, compared to the 15 % of the minor product. Hence, the reaction is efficient.
Answer: Ag^+ (aq) + NO3^-(aq) + Na^+ (aq) +Cl^- (aq) ⇒ AgCl(s) + NaNO3(aq)
