Answer: Bottom and top (or which ever one is the small box in the middle and the one that looks like the small box in the middle)
Step-by-step explanation: the middle rectangle is the bottom and the other one like it is the top. the length is 7 in. and the height is 4 in. and 4 in. times 7 in. is 28in^2
Let the area of the original rectangle be A₁.
A₁ = (12 ft)(8 feet) = 96 ft²
To determine the area of the reduced triangle, let's compute the new dimensions first.
Length = 12 ft * 3/4 - 9 ft
Width = 8 ft *3/4 = 6 ft
Thus, the area of the new rectangle denoted as A₂ is
A₂ = (9 ft)(6 ft) = 54 ft
The ratio of the areas are:
A₂/A₁ = 54/96 = 9/16
The ratio of the sides are given to be 3/4.
Finally the ratios of the area to side would be:
Ratio = 9/16 ÷ 3/4 = 3/4
Therefore, the ratio of the areas is 3/4 of the ratio of the corresponding sides.
Answer:
Eric's statement is false.
Step-by-step explanation:
When a positive and a negative number is added, pay attention to what number has a greater absolute value. If the positive number is greater, then the answer will be positive. In the negative number is greater, then the answer will be negative. For example, 23 + (-4) is going to end up as a positive sum, since 23 has a greater absolute value than -4. On the other hand, (-23) + 4 is going to end up as a negative number since -23 has a greater absolute value than 4.
Answer:
No, √3 is not rational. If you need more of an explanation let me know
Answer:
<u>Russell runs 9/50 of a mile or 0.18 miles in one minute.</u>
Step-by-step explanation:
1. Let's review the data given to us for solving the question:
Distance run by Russell = 9/10 of a mile
Time Russell runs 9/10 of a mile = 5 minutes
2. How many miles does he run in one minute?
Speed of Russell = Distance run by Russell / Time Russell runs
Speed of Russell = (9/10) / 5
Speed of Russell = 9/10 * 1/5 = 9/50
Russell runs 9/50 of a mile in one minute. If we want to express the answer in decimals, we have : 9/50 = 0.18
<u>Russell runs 9/50 of a mile or 0.18 miles in one minute</u>
