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4 years ago

HELP ME Four students each wrote an equation. Which two students wrote equations that have no solution?

Mathematics

2 answers:

rjkz [21]4 years ago

6 0

Answer:

Beto and Mark

Step-by-step explanation:

When you simplify Beto's equation, you get 0=5 which is inncorrect. 5 does not equal 0 so there are no solutions. When you simplify Mark's equation, you get 6=2 which is also inncorrect. 6 can not equal 2. If you solve the other 2 equations you get answers that can work.

Oxana [17]4 years ago

5 0

Beto and mark I think sorry if it is wrong

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Which equation correctly applies the associative property of multiplication

soldi70 [24.7K]

The second answer is correct since the associative property has the do with how you use parenthesis.

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4 years ago

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baherus [9]

1 second = 2 megabytes

$1\frac{1}{2}\ seconds=3\ megabytes$

2 seconds = 4 megabytes

Step-by-step explanation:

Given,

Time taken to download 5 megabytes = $2\frac{1}{2}=\frac{5}{2}$ seconds

$\frac{5}{2}\ seconds = 5\ megabytes$

Multiplying both sides by $\frac{2}{5}$ to find unit rate

$\frac{2}{5}*\frac{5}{2}\ second = \frac{2}{5}*5\\1\ second = 2\ megabytes$

1 second = 2 megabytes

$1\frac{1}{2}\seconds = \frac{3}{2}\ seconds$

$\frac{3}{2}\ seconds = \frac{3}{2}*2$

$\frac{3}{2}\ seconds = 3\ megabytes$

$1\frac{1}{2}\ seconds=3\ megabytes$

2 seconds = 2*2 megabytes

2 seconds = 4 megabytes

Keywords: fraction, multiplication

Learn more about fractions at:

#LearnwithBrainly

4 0

4 years ago

After a 3 hour snow storm there are 9 inches of snow on the road. What is the rate per inch?

Daniel [21]

Answer:

I inch per hour for 2 hours = 2 inches

2 inches per hour for 6 hours = 6*2 = 12 inches

1 inch per hour for 1 hour = 1 inch

2+12+1 = 15 inches of snow total

Step-by-step explanation:

credit to: musiclover10045

3 0

3 years ago

If the following ordered pairs are equal find x and y <br>a) (7x+3y,2x+3y)and(24,0)

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3 years ago

Prove 2√(x) + 1/√(x + 1) <= 2√(x+1) for all x in [0,inf)

EleoNora [17]

Start by multiplying each side of the inequality by $\sqrt{x + 1}$ and simplifying:

$2 \sqrt x + \frac{1}{\sqrt{x+1}} \leq 2 \sqrt{x + 1}$
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$2 \sqrt{x(x + 1)} + 1 \leq 2(x + 1)$
$2 \sqrt{x^2 + x} + 1 \leq 2x + 2$
$2 \sqrt{x^2 + x} \leq 2x + 1$
$\sqrt{x^2 + x} \leq x + \frac{1}{2}$

From here, we can square both sides to get

$x^2 + x \leq (x + \frac{1}{2})^2$
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3 years ago