Answer:
Time t = 2 seconds
It will reach the maximum height after 2 seconds
Completed question;
Amir stands on a balcony and throws a ball to his dog who is at ground level. The ball's height, in meters above the ground, after t seconds that Amir has thrown the ball is given by:
H (t) = -(t-2)^2+9
many seconds after being thrown will the ball reach its maximum height?
Step-by-step explanation:
The equation of the height!
h(t) = -(t-2)^2 + 9 = -(t^2 -4t +4) + 9
h(t) = -t^2 +4t -4+9
h(t) = -t^2 + 4t +5
The maximum height is at dh/dt = 0
dh/dt = -2t +4 = 0
2t = 4
t = 4/2 = 2
Time t = 2 seconds
It will reach the maximum height after 2 seconds
I think the answers would be B) 17
Answer:
Step-by-step explanation:
we know that
In this problem we have
substitute the given value in the formula and solve for F
2. The three points you need to mark on this graph are (1,2) (2,3) and (4,5); you then draw a line through all of these points and determine whether the inches of rainfall is proportionate to the number of hours.
You mark those 3 points because at 1 hour, 2 inches of rain has fallen; at 2 hours, 3 inches of rain has fallen; and at 4 hours, 5 inches of rain has fallen
Answer:
39
Step-by-step explanation:
Given the function :
h(t) = t² + 2
From t = 5 to t = 8
when, t = 5
h(5) = 5² + 2
h(5) = 25 + 2
h(t) at t = 5 ; equals 27
when, t = 8
h(5) = 8² + 2
h(5) = 64 + 2
h(t) at t = 8 ; equals 66
Net Change :
h(8). - h(5)
66 - 27 = 39
