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3 years ago

12

Solve the equation.

2 answers:

inna [77]3 years ago

8 0

Answer:

<h2><em>1</em></h2>

<em> $solution \\ 9 - 3 \div \frac{1}{3} + 1 \\ = 9 - 3 \times \frac{3}{1} + 1 \\ = 9 - 3 \times 3 + 1 \\ = 9 - 9 + 1 \\ = 9 + 1 - 9 \\ = 10 - 9 \\ = 1$ </em>

<em>Hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

Zinaida [17]3 years ago

6 0

Answer: 1

Step-by-step explanation:

9-3÷1/3+1

9-3×3+1

9-9+1

=1

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3 years ago

The perimeter of the rectangle is 22 meters, and the perimeter of the triangle is 12 meters. Find the dimensions of the rectangl

lianna [129]

Answer:

Length:8 m

Width:3 m

Step-by-step explanation:

<u><em>The complete question is</em></u>

If the perimeter of a rectangle is 22 meters, and the perimeter of a right triangle is 12 meters (the sides of the triangle are half the length of the rectangle, the width of the rectangle, and the hypotenuse is 5 meters). How do you solve for L and W, the dimensions of the rectangle.

step 1

<em>Perimeter of rectangle</em>

we know that

The perimeter of rectangle is equal to

$P=2(L+W)$

we have

$P=22\ m$

so

$22=2(L+W)$

Simplify

$11=L+W$ -----> equation A

step 2

Perimeter of triangle

The perimeter of triangle is equal to

$P=\frac{L}{2}+W+5$

$P=12\ m$

so

$12=\frac{L}{2}+W+5$

Multiply by 2 both sides

$24=L+2W+10$

$L+2W=14$ ----> equation B

Solve the system of equations by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

The solution is the point (8,3)

see the attached figure

therefore

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3 years ago

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Answer:

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2 years ago

The hypotenuse of a 45°-45°-90° triangle measures 22 2 units.

Aleonysh [2.5K]

Answer:

Option C.

Step-by-step explanation:

Given information: The hypotenuse of a 45°-45°-90° triangle measures 22√2 units.

Let x be the length of one leg.

From the given figure it is clear that length of both legs are same.

According to the Pythagoras theorem, in a right angled triangle

$(leg_1)^2+(leg_2)^2=hypotenuse^2$

Substitute $leg_1=leg_2=x, hypotenuse=22\sqrt{2}$ in the above formula.

$(x)^2+(x)^2=(22\sqrt{2})^2$

$2x^2=(22)^2(\sqrt{2})^2$

$2x^2=2(22)^2$

Divide both sides by 2.

$x^2=(22)^2$

Taking square root on both sides.

$x=22$

The length of one leg is 22 units.

Therefore, the correct option is C.

6 0

3 years ago

Read 2 more answers

marshall27 [118]

B:(3,-4)
2x-(-x-1)=10
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8 0

3 years ago

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