Well. I can't see the picture. But it would be decreasing at a rate of 4 so pick a point on the any line move over to the right one, then down four. And for the y intercept the line would intersect the y axis at positive one. Sorry if that's confusing
I flew past the whip with that blunt in my mouth
Watch the swervin', that whip had a cop in it (Woo)
In order to Sherman a line that is either parallel or perpendicular to another line, you first have to put the equation into slope intercept form. This means you have to solve for y.
3x+4y = 7
4y = -3x + 7
y = (-3/4)x + (7/4)
The slope of the line is -3/4. Online which is perpendicular would have a slope of 4/3, The negative reciprocal.
Now that you know the slope, you can write many different equations that would be perpendicular to the original.
y = (3/4)x + any y-intercept....Pick a number, any number... 7. ... y=(3/4)x+7
... -2 ...y = (3/4)x - 2. Literally you can pick any number.
Answer: The missing angle is 13°
Step-by-step explanation:
Let ∠B
be the missing angle.
Let ∠A
be the angle that measures
77∘Let ∠C
the right angle that measures
90∘
The following is true of all triangles:
∠A+∠B+∠C=180∘
Express the above equation as
∠B
in terms of the other angles:
∠B=180∘−∠A−∠C
Substitute the values for ∠A and ∠C
∠B=180∘−77∘−90∘
∠B=13∘
Step-by-step explanation:
x = 3 or x = -2 we dont use the (-2) because we have a sqrt
So x =3
