1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zhenek [66]
2 years ago
7

The melting point of each of 16 samples of a certain brand of hydrogenated vegetable oil was determined, resulting in ¯x = 94.32

. Assume that the distribution of the melting point is normal with σ = 1.20. (a) Test H0 : µ = 95 versus Ha : µ 6= 95 using a two-tailed level .01 test. (b) If a level .01 test is used, what is β(94), the probability of a type II error when µ = 94? (c) What value of n is necessary to ensure that β(94) = .1 when α = .01?
Mathematics
1 answer:
Degger [83]2 years ago
4 0

Answer:

Given:

Mean, x' = 94.32

s.d = 1.20

n = 16

a) For null hypothesis:

H0 : u= 95

For alternative hypothesis:

Ha : u≠95

Level of significance, a = 0.01

(Two tailed test)

We reject null hypothesis, h0, if P<0.01 level of significance.

Calculating the test statistic, we have:

Z = \frac{x' - u_0}{s.d / \sqrt{n}} = \frac{94.32-95}{1.20/ \sqrt{16}}

= -2.266

= -2.27

Calculating the P value:

P value = 2P(Z < -2.27)

Using the standard normal table,

NORMSDIST(-2.27)

= 0.0116

P value= 2(0.0116)

= 0.0232

Since P value(0.0232) is greater than level of significance (0.01), we fail to reject the null hypothesis H0.

We can say that there is enough evidence to conclude the data does not support that average melting point differs from the level of 95 at the level of 0.01 significance level.

b) B(u = 94)

= P(when u=94, do not reject H0)

Using the standard nkrmal table, the z-score corresponding to

Z(0.01/2)= 0.005 will be

Z_a_/_2 = 2.58

B(94) = ∅[Z_a_/_2+ \frac{u_0-u}{s.d- \sqrt{n}}] - ∅[-Z_a_/_2+ \frac{u_0-u}{s.d/ \frac{n}}]

B(94) = ∅[2.58+ \frac{95-94}{1.20- \sqrt{16}}] - ∅[-2.58+ \frac{95-94}{1.2/ \frac{16}}]

= ∅(5.91)-∅(0.75)

P(Z≤5.91)-P(Z≤0.75)

From standard normal table, we have:

P(Z≤0.75)=0.7734, P(Z≤5.91)=1

= 1 - 0.7734

= 0.2266

Probability of making type II error when u=94 is 0.2266

c) Probability of committing type II error when u= 94 at a significance level of 0.01 will be =0.10.

B(94) = 0.10

Finding sample size, n for a two tailed test:

n = [\frac{s.d(Z_a_/_2+Z_B)}{u_0-u}]^2

Using standard normal table, Z score corresponding to a/2 = 0.005 cummulative area(1-0.005 = 0.995) is Z= 2.58

Z score corresponding to 0.10 cummulative area(1-0.10 = 0.90) is Z = 1.28

Our sample size n, wil be=

n = [\frac{1.2(2.58+1.28)}{95-94}]^2

= [\frac{4.632}{1}]^2

= 21.46

= 22

Sample size = 22

You might be interested in
Please help i'm timed!!!!
MrRissso [65]

Answer:

The second one

Step-by-step explanation:

4 0
2 years ago
Help please and thank you
stiks02 [169]

First, we can see that there are four sides, and none of these equation contradict each other, so it is safe to say that <em>this is a quadrilateral</em>.

Second, all of the equations have the slope of <em>0 or undefined</em>, so it is a rectangle.

Lastly, the four points of intersection shows us that the side lengths are <em>3 and 5</em> units, so the area of it is 15 units².

7 0
3 years ago
Read 2 more answers
the number of pizzas eaten at the class party is equal to one-fourth and number of students plus two more pizzas for the adults
maria [59]
If s represents the number of students, then the number of pizzas is
  s/4 + 2 = 9
  s/4 = 7 . . . . . . subtract 2
  s = 28 . . . . . . multiply by 4

There are 28 students.
7 0
3 years ago
Part 1: Determine the domain.<br> DOMAIN:
DochEvi [55]

Answer:

The domain is -2 to positive 2.

5 0
3 years ago
Hey there I need some assistance need on this problem. What do I mean by checkpoints and how am I supposed to find the y-interce
MakcuM [25]

Slope Formula: y2 - y1 / x2 - x1

(m and slope represent the same quantity)

m = 1 - - 5 / -4 - 0

m = 1 + 5 / -4

m = 6 / -4

m = -3/2

Now that we know the slope, we can plug the slope and one of our points into slope-intercept form (y = mx + b) and solve for b. I will be using the point (-4,1).

y = -3/2x + b

1 = -3/2(-4) + b

1 = 6 + b

b = -5

In point form, the y-intercept is (0, -5).

Therefore, to get the equation all we need to do is plug in our slope and b-value to slope-intercept form.

Equation: y = -3/2 x - 5

To check the point (-6, -14) we plug it into our equation and see if the two sides are equal.

-14 = -3/2(-6) - 5

-14 = 9 - 5

-14 = 4

-14 does not equal 4, therefore the point is NOT on the line.

Hope this helps!

6 0
3 years ago
Other questions:
  • 1218÷6 I need help please
    12·2 answers
  • Food bill before tax: $30<br>Sales tax: 6.4% <br>Tip: 15%<br>Please help!
    7·1 answer
  • Determine whether the data described below are qualitative or quantitative and explain why.The shoe sizes left parenthesis such
    6·1 answer
  • For:<br> 9 times the sum of 9b and 2
    15·1 answer
  • Write the equation of the line for the graph shown below, please
    7·2 answers
  • Question #7: Which revolution resulted from the division of society shown in this diagram?
    12·1 answer
  • Estimate to find the quotient if 823 divided by 23​
    8·2 answers
  • Answer please You feeling lucky punk
    13·1 answer
  • There will be Elizabeth and Izak record the number of miles they bike each day. The line plots show the distances they each bike
    12·1 answer
  • It’s in the picture <br> P.S. the answer isn’t 64
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!