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aivan3 [116]
4 years ago
10

1/8 of a number is -4200. What is the number: -33,600 -37 800 -42,000 -42,800

Mathematics
1 answer:
Sav [38]4 years ago
8 0

Answer:

-33,600

Step-by-step explanation:

you already know that -4200 is 1/8 of the number so all you have to do is multiply -4200 by 8 and that gives -33,600.

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Suppose y varies directly with x, and y = 65 when x = 13. What direct variation equation relates x and y?
NISA [10]

Answer:

y = 5x

Step-by-step explanation:

y = kx

65 = k (13)

65/13 = k

k = 5

~~~~~~~~~~~~

y = 5x

6 0
3 years ago
Which number checks the equation 6x = x + 50?
galina1969 [7]
The answer is 10. You are welcome
7 0
4 years ago
A new car is purchased for 20000 dollars. The value of the car depreciates at 12. 5% per year. What will the value of the car be
Georgia [21]

To solve the problem we need to know about depreciation.

<h2>Formula of Depreciation</h2>

The formula of depreciation is given as,

A = P(1-r)^t

where,

A is the value of an object after t years of time,

P is the value of the object at the beginning, and

r is the rate of depreciation.

The value of the car after 11 years is $4,603.81.

<h2>Explanation</h2>

Given to us

  • Cost of Car at the beginning, p = $20,000
  • Rate of depreciation, r = 12.5%
  • Time, t = 11 years

<h3>Value of the car after 11 years</h3>

Substituting the values in the formula of depreciation,

A = P(1-r)^t

Value of the car after 11 years = P(1-r)^n

                                                 = \$20,000(1-0.125)^{11}\\\\&#10;= \$20,000\times 0.23\\\\&#10;= \$4,603.822 \approx \$4,603.81

Hence, the value of the car after 11 years is $4,603.81.

Learn more about Depreciation:

brainly.com/question/3023490

8 0
3 years ago
What is the shape of a parallel cross section of a sphere?
sertanlavr [38]
The answer is a circle. Hope this helped :)
4 0
3 years ago
Read 2 more answers
What are the missing parts that correctly complete the proof
bonufazy [111]

Answer:

2. \overline{AX}\cong \overline{BX}

3. PX \perp AB - definition of perpendicular

4. \angle PXA \cong \angle PXB - all right angles are congruent

6. \triangle AXP\cong \triangle BXP

7. \overline{PA} \cong \overline{PB}

Step-by-step explanation:

<u>Given: </u>Point P is the perpendicular bisector of AB

<u>Prove: </u>P is equidistant from the endpoints AB

<u>Proof.</u>

1. Point P is on the perpendicular bisector of AB - given

2.\overline{AX}\cong \overline{BX} - definition of bisector

3. PX \perp AB - definition of perpendicular

4.  \angle PXA \cong \angle PXB - all right angles are congruent

5. \overline{PX} \cong \overline{PX} - reflexive property of congruence

6. \triangle AXP\cong \triangle BXP - SAS congruency postulate

7. \overline{PA} \cong \overline{PB} - corresponding parts of congruent triangles are congruent

8. Point P is equidistant from the endpoints of AB - definition of equidistant

5 0
3 years ago
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