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jekas [21]
4 years ago
5

the cost of a ticket to a park is 42 per person for a group of 8 people the cost per ticket decreses by 3 for each person in the

group marcos ticket cost 30 write and solve an equation to find the number of people in the group
Mathematics
1 answer:
JulijaS [17]4 years ago
8 0

42 \times 8  \div 3 \
then
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John wants to measure the height of a tree.he walks exactly 100 ft from the base of the tree and looks up.the angle from the gro
kati45 [8]

Answer: The height of the tree is 64.94ft

Step-by-step explanation:

Using the trigonometry of angles

Tan theta = opposite/adjacent

Tan 33° = height of the tree/100

Height of the tree= tan 33° * 100

= 0.6494*100

= 64.94ft

The height of the tree is 64.94ft

6 0
3 years ago
If one endpoint is (-6,4) and the midpoint is (4,8) what would be the other endpoint ???? if you can explain it would be great
krek1111 [17]
I believe the next one would be 13.2 because if you add 8.4 to -6.4 it gets 4.8 so you just do the same thing
8 0
3 years ago
Please right now I need help
ollegr [7]

Answer:

3

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
An expression is shown below: 2x3y + 18xy − 10x2y − 90y Part A: Rewrite the expression by factoring out the greatest common fact
SCORPION-xisa [38]

Answer:

Part A : 2y( x³ + 9x - 5x² - 45 ), Part B : 2y( x - 5 )( x² + 9 )

Step-by-step explanation:

Part A : Let's break every term down here to their " prime factors ", and see what is common among them,

2x³y + 18xy − 10x²y − 90y -

2x³y  = 2 * x³ * y,

18xy = 2 * 3 * 3 * x * y,

− 10x²y = 2 * - 5 * x² * y, - so as you can see for this example I purposely broke down - 10 into 2 and - 5. I could have placed the negative on the 2, but as that value was must likely common among all the terms, I decided to place it on the 5. The same goes for " − 90y. " I placed the negative there on the 5 once more.

− 90y = 2 * - 5 * 3 * 3 * y

The terms common among each term are 2 and y. Therefore, the GCF ( greatest common factor ) is 2x. Let's now factor the expression using this value.

2y( x³ + 9x - 5x² - 45 )

Part B : Let's simply factor this entire expression. Of course starting with the " factored " expression : 2y( x³ + 9x - 5x² - 45 ),

2y\left(x^3+9x-5x^2-45\right) - Factor out " (x^3+9x-5x^2-45\right)) " by grouping,

\left(x^3-5x^2\right)+\left(9x-45\right) - Factor 9 from 9x - 45 and x² from x³ - 5x²,

9\left(x-5\right)+x^2\left(x-5\right) - Factor out common term x - 5,

\left(x-5\right)\left(x^2+9\right) - And our solution is thus 2y( x - 5 )( x² + 9 )

3 0
4 years ago
Plz help, The graph of y = f(x) is shown below. What are all of the real solutions of f(x) = 0?
8_murik_8 [283]

Answer:

The real solutions of f(x)=0 are: 0, 2, 5, 6

Step-by-step explanation:

We are given:

The graph of y = f(x)

We need to find all of the real solutions of f(x) = 0?

By looking at the graph we need to find the values of y when x =0

Looking at the graph, when x=0 we get

0, 2,5 and 6

So, the real solutions of f(x)=0 are: 0, 2, 5, 6

I am attaching the figure, that determines the answers.

8 0
3 years ago
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