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Pie
3 years ago
11

4. Suppose a security light is set into the ground and aims its light at the top of the building. The angle of elevation of the

light is 60 degrees. The building is 9 feet tall. a. What is the distance of the light's base from the bottom of the building? Use a trig function to calculate the distance. b. How long is the light beam? light beam. Use a trig function to calculate the length of the
Mathematics
1 answer:
brilliants [131]3 years ago
7 0

Answer:

a) The distance of the light's base from the bottom of the building is approximately: 5.2 ft

b) The length of the beam is approximately: 10.4 ft

Step-by-step explanation:

First, we have to recognize that we may draw a right triangle to picture our problem. Then, in order to find out the distance of the light's base from the bottom of the building, we need to use the tangent trigonometric function:

tan(angle) = opposite side / adjacent side

We know the angle and the opposite side and we want to find the adjacent side:

adjacent side = opposite side / tan(angle) = 9 ft / tan(60°) = 9 ft / = 9 ft / 1.73 = 5.2 ft

In order to find the length of the light  beam, we use Pythagoras Theorem:

leg1²+leg2² = hyp²

Since the length of the beam corresponds to the hypotenuse and since we already know the length of the two legs, it is just a matter of substituting the values:

hyp = square_root(leg1²+leg2²) = square_root(9² + 5.2²) ft = square_root(108.4) ft = 10.4 ft

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Jackie bought a 3-pack of tubes of glue. She used 0.27 ounce of the glue from the 3-pack
brilliants [131]

Answer:

0.54 ounces in each tube

Step-by-step explanation:

Add the amount she used so we can add it in. 1.35+0.27= 1.62. Then divide it by the number of tube and since it was a 3 pack you divide it by 3. 1.62/3=0.54 so there is 0.54 ounces in each tube.

5 0
3 years ago
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What are the discontinuities of the function f(x) = x^2+2x-8/12x+24?
Advocard [28]
Factor the numerator and denominator of the function to find holes, vertical asymptotes, and horizontal asymptotes.
Numerator: (x - 2)(x + 4)
Denominator: 12(x + 2)
This would mean there is infinite discontinuity at x = -2 (the vertical asymptote).
8 0
4 years ago
Grandpa gump is 63yrs old. His age is 2 years less than 5 times the age of billy Gump. How old is Billy?
AveGali [126]

5x -2  =  63

<u>     +2 = +2 (add 2 to both sides)</u>

<u>5x       = 65  (your equation)</u>

5              5 (divide both sides by 5)

x        = 13

Billy is 13 years old.

(check: 13 x 5 - 2 = 63

6 0
3 years ago
A survey was conducted by an independent price-checking company to check an advertiser's claim that it had lower prices than its
Lisa [10]

Answer:

Pvalue > α ; We fail to reject the Null; hence no significant difference exists in the average prices of the two supermarkets.

(−68.1095 ; 57.8545)

Step-by-step explanation:

Given the data:

Week Advertiser ($) Competitor ($) 1 254.27 255.93 2 240.72 255.65 3 231.91 255.12 4 234.15 261.28

Difference, d :

254.27 - 255.93 = - 1 66

240.72 - 255.65 = - 14.93

231.91 - 255.12 = - 23.21

234.15 - 261.28 = - 27.13

d = -1.66, -14.93, 23.21, -27.13

Using calculator :

Mean difference , dbar = - 5.1275

Standard deviation of mean , Sd = 21.566

H0 : μd = 0

H1 : μd ≠ 0

Test statistic :

(dbar - μd) / s/√n

(-5.1275 - 0) / (21.566/√4)

-5.1275 / 10.783

= −0.475517

Using the Pvalue from Tscore Calculator ; df = 4 - 1 = 3

Pvalue = 0.66659

Pvalue > α ; We fail to reject the Null; hence no significant difference exists in the average prices of the two supermarkets.

Confidence interval :

dbar ± standard Error

Standard Error = Tcritical * Sd/√n

dbar = - 5.1275

Tcritical at 0.01 = 5.941

Standard Error = 5.8409 * 21.566/√4 = 62.982

Confidence interval :

Lower boundary : - 5.1275 - 62.982 = −68.1095

Upper boundary = - 5.1275 + 62.982 = 57.8545

(−68.1095 ; 57.8545)

The true population on difference exist within the interval

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3 years ago
From a boat on the lake, the angle of elevation to the top of a cliff is 27°57'. If the base of the cliff is 128 feet from the b
Len [333]
Here is your genuine answer

3 0
3 years ago
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