I don’t understand this

Suppose there are some chairs in a room and that each chair has 4 legs.

RideAnS [48]

Answer:

y = 4x / x = 1/4 y

Step-by-step explanation:

chairs = x ( to find out how many chairs there are you have to take the legs and divide them by 4 )

Legs = y ( to find out how many legs there are you must multiply the amount of chairs by 4 )

5 0

3 years ago

Help asap giving Brainlist!!!

Rzqust [24]

Answer:

1st question

A) no the table does not represent a linear function

B) the slope ( average rate of change)is 2

2nd question

A) yes the table represent a linear function

B) the slope( average rate of change) is 6

I hope u get what ur looking for and I wish u give me brainlist But I know u won’t bcz everyone say that . But thank you so much if u put for me and It would be a very appreciated from you and again thank you so much

Sincerely Caitlin ,

Thank you ☺️

5 0

3 years ago

Find the absolute extrema for f(x,y)=4-x^2-y^4+1/2y^2 over the closed disk D:x^2+y^2 is less than or equal to 1

algol [13]

Find the critical points of $f(x,y)$ :

$\dfrac{\partial f}{\partial x}=-2x=0\implies x=0$

$\dfrac{\partial f}{\partial y}=y-4y^3=y(1-4y^2)=0\implies y=0\text{ or }y=\pm\dfrac12$

All three points lie within $D$ , and $f$ takes on values of

$\begin{cases}f(0,0)=4\\f\left(0,-\frac12\right)=\frac{65}{16}\\f\left(0,\frac12\right)=\frac{65}{16}\end{cases}$

Now check for extrema on the boundary of $D$ . Convert to polar coordinates:

$f(x,y)=f(\cos t,\sin t)=g(t)=4-\cos^2-\sin^4t+\dfrac12\sin^2t=3+\dfrac32\sin^2t-\sin^4t$

Find the critical points of $g(t)$ :

$\dfrac{\mathrm dg}{\mathrm dt}=3\sin t\cos t-4\sin^3t\cos t=\sin t\cos t(3-4\sin^2t)=0$

$\implies\sin t=0\text{ or }\cos t=0\text{ or }\sin t=\pm\dfrac{\sqrt3}2$

$\implies t=n\pi\text{ or }t=\dfrac{(2n+1)\pi}2\text{ or }\pm\dfrac\pi3+2n\pi$

where $n$ is any integer. There are some redundant critical points, so we'll just consider $0\le t< 2\pi$ , which gives

$t=0\text{ or }t=\dfrac\pi3\text{ or }t=\dfrac\pi2\text{ or }t=\pi\text{ or }t=\dfrac{3\pi}2\text{ or }t=\dfrac{5\pi}3$

which gives values of

$\begin{cases}g(0)=3\\g\left(\frac\pi3\right)=\frac{57}{16}\\g\left(\frac\pi2\right)=\frac72\\g(\pi)=3\\g\left(\frac{3\pi}2\right)=\frac72\\g\left(\frac{5\pi}3\right)=\frac{57}{16}\end{cases}$

So altogether, $f(x,y)$ has an absolute maximum of 65/16 at the points (0, -1/2) and (0, 1/2), and an absolute minimum of 3 at (-1, 0).

5 0

3 years ago

What values of a, b, and c would you use in the quadratic formula for the following equation? 6x^2+5x-4=0

Yanka [14]

So remember that in a quadratic equation there is a type of quadratic equation of the form ax^2+bx+c=0 so to find what values of a, b, and c you need for the quadratic formula, you need to look at your equation and label a, b, and c. In this equation a=6, b=5 and c=-4. So for the quadratic formula you would use a=6, b=5 and C=-4. I hope this helps!!!!!

5 0

3 years ago

Select all the solutions to <br> ( x - 2) to the power of 2 = -16

leonid [27]

The answer are both:
x=2+4i,2-4i

4 0

3 years ago