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Zanzabum
2 years ago
13

Cuánto es 1+1 = es dos jaja​

Mathematics
2 answers:
Kisachek [45]2 years ago
8 0
Ok bro, this is 2 but like i speak english
ss7ja [257]2 years ago
4 0

Answer:

El raigañu cuadráu corresponder cola radicación d'índiz 2 o, equivalentemente, cola potenciación d'esponente 1/2.

Cualquier númberu real non negativu {\displaystyle x}x tien un únicu raigañu cuadráu positiva o raigañu cuadráu principal[2] y denotada como {\displaystyle {\sqrt {x}}}{\displaystyle {\sqrt {x}}} onde {\displaystyle {\sqrt {\;}}}{\displaystyle {\sqrt {\;}}} ye'l símbolu raigañu y {\displaystyle x}x ye'l aniciando.

Cuando se riquir denotar dos raigaños cuadraos una negativa, {\displaystyle -{\sqrt {x}}}{\displaystyle -{\sqrt {x}}}, y otra positiva, {\displaystyle {\sqrt {x}}}{\displaystyle {\sqrt {x}}}, suelen denotarse curioso como {\displaystyle \pm {\sqrt {x}}}{\displaystyle \pm {\sqrt {x}}} o bien como {\displaystyle \mp {\sqrt {x}}}{\displaystyle \mp {\sqrt {x}}} según l'orde precisáu.

El conceutu de raigañu cuadráu puede estendese a cualquier aniellu alxebraicu, asina ye posible definir el raigañu cuadráu d'un númberu real negativu o'l raigañu cuadráu de delles matrices. Nos númberos cuaterniónicos los reales negativos almiten un númberu infinitu de raigaños cuadraos, sicasí'l restu de cuaterniones distintos de cero almiten solu dos raigaños cuadraos. Nel aniellu non conmutativu de les funciones reales de variable real cola adición y la composición de funciones si fºf = g, puede plantegase que f ye la "raigañu cuadráu" de g.[3]

Step-by-step explanationY segun todos mis calculos es 2 :

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Anuta_ua [19.1K]

Answer:

\sin(105) = \frac{\sqrt 2 + \sqrt 6}{4}

Step-by-step explanation:

Given

\sin(105^o)

Required

Solve

Using sine rule, we have:

\sin(A + B) = \sin(A)\cos(B) + \sin(B)\cos(A)

This gives:

\sin(105^o) = \sin(60 + 45)

So, we have:

\sin(60 + 45) = \sin(60)\cos(45) + \sin(45)\cos(60)

In radical forms, we have:

\sin(60 + 45) = \frac{\sqrt 3}{2} * \frac{\sqrt 2}{2} + \frac{\sqrt 2}{2} * \frac{1}{2}

\sin(60 + 45) = \frac{\sqrt 6}{4} + \frac{\sqrt 2}{4}

Take LCM

\sin(60 + 45) = \frac{\sqrt 6 + \sqrt 2}{4}

Rewrite as:

\sin(60 + 45) = \frac{\sqrt 2 + \sqrt 6}{4}

Hence:

\sin(105) = \frac{\sqrt 2 + \sqrt 6}{4}

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