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suter [353]
3 years ago
11

Let f be a function such that f(x)=2x-4 is defined on the domain.2 is less than or equal to x and x is lss than or equal to 6. T

he range of the function
Mathematics
2 answers:
STALIN [3.7K]3 years ago
8 0
F(x) = 2x - 4
f(2 ≤ x) = 2(2 ≤ x) - 4
f(x ≥ 2) = 2(x ≥ 2) - 4
f(x ≥ 2) = 2(x) ≥ 2(2) - 4
f(x ≥ 2) = 2x ≥ 4 - 4
f(x ≥ 2) = 2x ≥ 0
f(x ≥ 2) = x ≥ 0

f(x) = 2x - 4
f(x ≤ 6) = 2(x ≤ 6) - 4
f(x ≤ 6) = 2(x) ≤ 2(6) - 4
f(x ≤ 6) = 2x ≤ 12 - 4
f(x ≤ 6) = 2x ≤ 8
f(x ≤ 6) = x ≤ 4
iris [78.8K]3 years ago
7 0
The range of the function is the set of values it can achieve.  The minimum value plugs in 2 to get 2*2-4, or 0.  The maximum value uses 6, and is 6*6-4, or 8.  Thus, the range is 0 to 8, inclusive.
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Solve for y:-<br><br> y + 17 = 21<br><br> Thanks!
S_A_V [24]
To solve for y we have to use the INVERSE OPERATION of addition which is subtraction Lets do it:-

y + 17 = 21
y = ?
21 - 17 = y
21 - 17 = 4
y = 4

CHECK OUR WORK:-

y + 17 = 21
y = 4
4 + 17 = ?
4 +17 = 21
We were RIGHT!!!!

So, y = 4.

Hope i helped ya!! xD
5 0
3 years ago
Read 2 more answers
-7(x-2)+5(3-x)-4x whats the equation
aleksandrvk [35]

Answer: -16x+29

Step-by-step explanation:

-7(x-2)+5(3-x)-4x

-7x+14+15-5x-4x

-12x-4x+29

-16x+29

4 0
3 years ago
Plot all ordered pairs for the values in the domain D: (-8, -4, 0, 2, 6)
alexdok [17]

All ordered pairs for the values in the domain will be (-8, -3), (-4, -1), (0, 1), (2, 2), and (6, 4).

<h3>What is coordinate geometry?</h3>

Coordinate geometry is the study of geometry using the points in space.

The function is given below.

y = (1/2) x + 1

Then the domain is D: (-8, -4, 0, 2, 6)

Then the ordered pair will be

For x = -8

y = (1/2)(-8) + 1

y = -3

For x = -4

y = (1/2)(-4) + 1

y = -1

For x = 0

y = (1/2)(0) + 1

y = 1

For x = 2

y = (1/2)(2) + 1

y = 2

For x = 6

y = (1/2)(6) + 1

y = 4

All ordered pairs for the values in the domain will be (-8, -3), (-4, -1), (0, 1), (2, 2), and (6, 4).

More about the coordinate geometry link is given below.

brainly.com/question/1601567

#SPJ1

3 0
1 year ago
An equation of the circle whose center is the origin and
tankabanditka [31]

Answer:

\fbox{\begin{minipage}{10em}Option C is correct\end{minipage}}

Explanation:

A circle whose center is (a, b) and radius r, has equation:

(x - a)^{2} + (y - b)^{2} = r^{2}

The center of circle is  given as origin (0, 0), therefore:

a = 0\\b = 0

This circle passes (3, 0), then the radius of circle is the distance (d) between origin (0, 0) and (3, 0)

d = \sqrt{(0 - 3)^{2} + (0 - 0)^{2} } = \sqrt{3^{2} } = 3

=> r = d = 3

Substitute a, b, and r back into original equation:

(x - 0)^{2} + (y - 0)^{2}  = 3^{2}

or

x^{2} + y^{2} = 9

Hope this helps!

:)

3 0
3 years ago
Find the equation of the line perpendicular to y=3/2x-9 and passes through the point (6,2)​
lys-0071 [83]

Answer:

y=-2/3x-2

Step-by-step explanation:

slope= -2/3

y=-2/3x+b

enter the given points

2=4+b

b=-2

y=-2/3x-2

6 0
2 years ago
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