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suter [353]
3 years ago
11

Let f be a function such that f(x)=2x-4 is defined on the domain.2 is less than or equal to x and x is lss than or equal to 6. T

he range of the function
Mathematics
2 answers:
STALIN [3.7K]3 years ago
8 0
F(x) = 2x - 4
f(2 ≤ x) = 2(2 ≤ x) - 4
f(x ≥ 2) = 2(x ≥ 2) - 4
f(x ≥ 2) = 2(x) ≥ 2(2) - 4
f(x ≥ 2) = 2x ≥ 4 - 4
f(x ≥ 2) = 2x ≥ 0
f(x ≥ 2) = x ≥ 0

f(x) = 2x - 4
f(x ≤ 6) = 2(x ≤ 6) - 4
f(x ≤ 6) = 2(x) ≤ 2(6) - 4
f(x ≤ 6) = 2x ≤ 12 - 4
f(x ≤ 6) = 2x ≤ 8
f(x ≤ 6) = x ≤ 4
iris [78.8K]3 years ago
7 0
The range of the function is the set of values it can achieve.  The minimum value plugs in 2 to get 2*2-4, or 0.  The maximum value uses 6, and is 6*6-4, or 8.  Thus, the range is 0 to 8, inclusive.
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Answer:

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Step-by-step explanation:

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y = 11^{(6x-x^2)}=exp((6x-x^2)ln(11))

so to know the maximum to y we can check the maximum of

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f'(x)=0 <=> x = 3

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to be rigorous, we can write the variation table of y to show that there is only one maximum

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