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suter [353]
3 years ago
11

Let f be a function such that f(x)=2x-4 is defined on the domain.2 is less than or equal to x and x is lss than or equal to 6. T

he range of the function
Mathematics
2 answers:
STALIN [3.7K]3 years ago
8 0
F(x) = 2x - 4
f(2 ≤ x) = 2(2 ≤ x) - 4
f(x ≥ 2) = 2(x ≥ 2) - 4
f(x ≥ 2) = 2(x) ≥ 2(2) - 4
f(x ≥ 2) = 2x ≥ 4 - 4
f(x ≥ 2) = 2x ≥ 0
f(x ≥ 2) = x ≥ 0

f(x) = 2x - 4
f(x ≤ 6) = 2(x ≤ 6) - 4
f(x ≤ 6) = 2(x) ≤ 2(6) - 4
f(x ≤ 6) = 2x ≤ 12 - 4
f(x ≤ 6) = 2x ≤ 8
f(x ≤ 6) = x ≤ 4
iris [78.8K]3 years ago
7 0
The range of the function is the set of values it can achieve.  The minimum value plugs in 2 to get 2*2-4, or 0.  The maximum value uses 6, and is 6*6-4, or 8.  Thus, the range is 0 to 8, inclusive.
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your class sponsors a benefit concert and the tickets at $8 each.Jordan sells 12 tickets,Andy 16,Morgan 17,and Pat 13.Compute th
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Algebra 2, I need help!!! Solve x^2 + 6x + 7 = 0. If you are going to comment in here please know the answer, this is so serious
docker41 [41]

Answer:

Third option

Step-by-step explanation:

We can't factor this so we need to use the quadratic formula which states that when ax² + bx + c = 0, x = (-b ± √(b² - 4ac)) / 2a. However, we notice that b (which is 6) is even, so we can use the special quadratic formula which states that when ax² + bx + c = 0 and b is even, x = (-b' ± √(b'² - ac)) / a where b' = b / 2. In this case, a = 1, b' = 3 and c = 7 so:

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6 0
3 years ago
Complete the square: x^2-8x+21=6<br><br> Please show work
mina [271]

Answer:

x=5 and 3

Step-by-step explanation:

x^2-8x+21=6

x^2-8x+21+16=6+16

(x-4)^2=1

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5 0
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Find the value of x,
Gekata [30.6K]

Answer: x = -7

Concept:

From the given graph, we can see that it is an isosceles triangle since the two base angles are congruent.

In geometry, an isosceles triangle is a triangle that has two sides of equal length.

If you are still confused, you may refer to the attachment below for a graphical explanation or tell me.

Solve:

<u>Given information</u>

First Side = 7

Second Side = x + 14

<u>Given expression deducted from the definition of an isosceles triangle</u>

Second Side = First Side

<u>Substitute values into the expression</u>

x + 14 = 7

<u>Subtract 14 on both sides</u>

x + 14 - 14 = 7 - 14

\boxed{x=-7}

Hope this helps!! :)

Please let me know if you have any questions

5 0
3 years ago
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