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aliina [53]
3 years ago
6

A gas sample has an initial volume of 55.2 mL, an initial temperature of 35.0 °C, and an initial pressure of 735 mm Hg. The volu

me is decreased to 48.8 mL and the temperature is increased to 72.5 °C. What is the final pressure?
Chemistry
1 answer:
Zielflug [23.3K]3 years ago
7 0

Answer:

The answer to your question is   P2 = 932.6 mmHg

Explanation:

Data

Volume 1 = V1 = 55.2 ml

Temperature 1 = T1 = 35°C

Pressure 1 = P1 = 735 mmHg

Volume 2 = V2 = 48.8 ml

Temperature 2 = T2 = 72.5°C

Pressure 2 = P2 = ?

Process

1.- Convert temperature to °K

Temperature 1 = 35 + 273 = 308 °K

Temperature 2 = 72.5 + 273 = 345.5°K

2.- Use the Combine gas law to solve this problem

               P1V1/T1 = P2V2/T2

-Solve for P2

               P2 = P1V1T2 / T1V2

-Substitution

               P2 = (735 x 55.2 x 345.5) / (308 x 48.8)

-Simplification

               P2 = 14017626 / 15030.4

-Result

               P2 = 932.6 mmHg

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An atom of an element has 54 protons. Some of the elements atoms have 77 neutrons, while other atoms have 79 neutrons. What are
Alja [10]

Answer:

The atomic numbers of both are 54 while the mass numbers are 131 and 133 respectively.

Explanation:

- The number of protons = Atomic number. So, if the atom has 54 protons and it remained unchanged, then the two types of atoms of this element both have atomic numbers of 54.

- On the other hand, mass number is the sum of protons and neutrons

So, if type 1 has protons = 54 and neutrons = 77: mass number = 54 + 77 = 131

if Type 2 has protons = 54 and neutrons = 79: mass number = 54 + 77 = 133

(Since the possibility of atoms of the same element to have different mass numbers but the same atomic number is called isotopy). The two types of atoms with mass numbers 131 and 133 described are isotopes.

7 0
3 years ago
Determine the partial negative charge on the bromine atom in a c−br bond. the bond length is 1.93 å and the bond dipole moment i
vaieri [72.5K]

Answer:

The value is x  =  0.151  \ e

Explanation:

From the question we are told that

The bond length is l  =  1.93\  \r  a =  1.93 *1 *10^{-10}  =1.93 *10^{-10}\  m

The bond dipole moment is \mu  = 1.40 d  = 1.40 *  3.33564 *10^{-30}  =  4.6699 *10^{-30} \  C \cdot m

Generally the dipole moment is mathematically represented as

\mu  =  Q *  l

Here Q is the partial negative charge on the bromine atom

So

Q =  \frac{\mu}{ l}

=> Q =  \frac{4.6699 *10^{-30}}{ 1.93 *10^{-10} }

=> Q = 2.42 *10^{-20} C

Generally

1 electronic charge(e) is equivalent to 1.60*10^{-19} C

So x electronic charge(e) is equivalent to Q = 2.42 *10^{-20} C

=> x  =  \frac{2.42 *10^{-20}}{1.60*10^{-19} }

=>     x  =  0.151  \ e

3 0
3 years ago
The concentration of hydroxide ions is less than the concentration of hydronium ions for acidic solutions. True False
wolverine [178]

Answer:

True

Explanation:

It's true because the pH is a measure of how basic or acid a solution is. In an acidic medium, the pH scales goes from 0 to 7. While in a basic medium goes from 7 to 14. The lower the pH value of the most acid the solution is.

1. The expression pH = -log(molar concentration of hydronium) allow to calculate the pH of a solution.

2. On the other hand, the expression pOH = -log(molar concentration of hydroxide) allow to determine the pOH of a solution.

The values of pH and pOH always obey the following expression:

pH + pOH = 14

Thus if for instance the pH becomes smaller the pOH must become bigger in order to fulfill the equation. Which means that the concentration of hydronium ions is greater than the hydroxide concentration.

For example, in an acidic medium:

if pH= 3, pOH= 11

In this case the molar concentration of hydronium is 0,001M. And the molar concentration of hydroxide ions is just 0,00000000001M.

4 0
3 years ago
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the nucleus of an atom consists of 8 protons and 6 neutrons the total of number of electrons present in a neutral atom of this e
nexus9112 [7]
The element that isn't combined has the same electrons as protons, then it is 8 electrons.
6 0
3 years ago
What is an example of a scope three carbon emission?
MAXImum [283]

Production of materials and transportation are the examples of three carbon emission.

Extraction and production of purchased materials and transportation of purchased fuels are the examples of three carbon emission. Scope 3 emissions refers to all indirect emissions that occur in the chain of the reporting company that is included in both upstream and downstream emissions.

Big machineries are used for the production and extraction of materials as well as the transportation requires fossil fuels for working which releases carbondioxide gas in the atmosphere so we can conclude that production of materials and transportation are the examples of three carbon emission.

5 0
3 years ago
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