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3 years ago

Who is Robert Hooke?

Chemistry

2 answers:

masya89 [10]3 years ago

5 0

Robert Hooke was an English natural philosopher, architect and polymath.

Paha777 [63]3 years ago

3 0

Physicist who discovered the Hookes Law that is the law of elasticity

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Copper conducts heat well.

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3 years ago

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6-11<br>don't answer if you don't know

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Answer:

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Explanation:

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3 years ago

How can a solution become saturated?

vladimir2022 [97]

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2 years ago

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Name the following ester molecule:OA. ethyl butanoateB. propyl pentanoateC. methyl heptanoateD. methylpropanoate

disa [49]

Answer

A. ethyl butanoate

Explanation:

Esters are known for their distinctive odors and are commonly used for food aroma and fragrances. The general formula of an ester is RCOOR'.

Esters are formed through reactions between an acid and an alcohol with the elimination of water.

Esters are named as if the alkyl chain from the alcohol is a substituent. No number is assigned to this alkyl chain. This is followed by the name of the parent chain from the carboxylic acid part of the ester with an –e remove and replaced with the ending –oate.

Hence, the name of the given ester is:

A. ethyl butanoate

8 0

1 year ago

The Pfund series of lines in the emission spectrum of hydrogen corresponds to transitions from higher excited states to the n =

lys-0071 [83]

Answer:

$\large \boxed{\text{4650 nm}}$

Explanation:

The second line in the Pfund series corresponds to a transition from n = 7 to n = 5.

To calculate the wavelength of the transition, we can use the Rydberg equation:

$\dfrac{1}{\lambda} = R_{H}\left ( \dfrac{1 }{n_{1}^{2}} - \dfrac{1 }{n_{2}^{2}} \right )$

where

$R_{H} = 1.097 \times 10^{7} \text{ m}^{-1}$

If n₁ = 5 and n₂ = 7

$\begin{array}{rcl}\dfrac{1}{\lambda} & = & 1.097 \times 10^{7} \text{ m}^{-1}\left ( \dfrac{1 }{5^{2}} - \dfrac{1 }{7^{2}} \right )\\\\ & = & 1.097 \times 10^{7} \text{ m}^{-1}\left ( \dfrac{1 }{25} - \dfrac{1 }{49} \right )\\\\ & = & 1.097 \times 10^{7} \text{ m}^{-1}\left ( \dfrac{49 - 25 }{49 \times25}\right )\\\\& = & 1.097 \times 10^{7} \text{ m}^{-1}\left ( \dfrac{24 }{1225}\right )\\\\ & = & 2.149 \times 10^{7}\text{ m}^{-1}\\\end{array}\\$

$\begin{array}{rcl}\lambda & = & \dfrac{1}{2.149 \times 10^{7}\text{ m}^{-1}}\\\\ & = & 4.65 \times 10^{-6} \text{ m}\\ & = & \mathbf{4650} \textbf{ nm}\\\end{array}\\\text{The wavelength of the line is $\large \boxed{\textbf{4650 nm}}$, which is in the $\textbf{infrared region}$}.$

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3 years ago