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nadya68 [22]
4 years ago
11

Who is Robert Hooke?

Chemistry
2 answers:
masya89 [10]4 years ago
5 0
Robert Hooke was an English natural philosopher, architect and polymath.
Paha777 [63]4 years ago
3 0
Physicist who discovered the Hookes Law that is the law of elasticity
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Do you know how to do this? if you have 4 grams of carbon-14, how much carbon 14 remains after 11,460 years? the half life is 5,
Delvig [45]
Carbon dating has<span> given archeologists a more accurate method by which they </span>can<span> determine the age of ancient artifacts. The </span>halflife<span> of </span>carbon 14<span> is </span>5730<span> ± 30 </span>years<span>, and the method of dating lies in trying to determine how </span>much carbon 14<span> (</span><span>the radioactive isotope of carbon) is present in the artifact and comparing it to levels</span>
6 0
3 years ago
Calculate the molarity of sodium chloride in a half-normal saline solution (0.45% NaCl). The molar mass of NaCl
Cerrena [4.2K]

Answer:

0.077 M

Explanation:

Molarity is the representation of the solution.

Molarity:

It is amount of solute in moles per liter of solution and represented by M

Formula used for Molarity

                    M = moles of solute / Liter of solution . . . . . . . . . . (1)

Data Given :

The concentration of half normal (NaCl) saline = 0.45g / 100 g

So,

Volume of Solution =  100 g = 100 mL

Volume of Solution in L =  100 mL / 1000

Volume of Solution =  0.1 L

molar mass of NaCl = 58.44 g/mol

Now to find number of moles of Nacl

               no. of moles of NaCl = mass of NaCl / molar mass

               no. of moles of NaCl =  0.45g / 58.44 g/mol

               no. of moles of NaCl =  0.0077 g

Put values in the eq (1)

                  M = moles of solute / Liter of solution . . . . . . . . . . (1)

                  M = 0.0077 g / 0.1 L

                  M = 0.077 M

So the molarity of half-normal saline solution (0.45% NaCl) = 0.077 M

3 0
3 years ago
On what basis can mixtures be classified as solutions suspensions or colloids
FinnZ [79.3K]

Answer:

A mixture is classified as a solution when there is an homogeneous mixture of the two or more substances involved in a given medium.

A mixture is classified as a suspension when there is a heterogeneous mixture of undissolved particles in a given medium.

A mixture is classified as a colloid (false solution) when the individual solute Particles are larger than the particles of true solution, but they are not large enough to be seen by the naked eye. The solutes can scatter light rays.

7 0
4 years ago
Where does baby came from​
Oksanka [162]

Answer:

they came from for the dad sperm

6 0
3 years ago
What is the vapor pressure of the pure solvent if the vapor pressure of a solution of 10 g of sucrose (C6H12O6) in 100 g of etha
amid [387]

Answer:

56.4 mmHg

Explanation:

Given:

Vapor pressure of the solution, P solution = 55 mmHg

The mass of sucrose (C₆H₁₂O₆) = 10 g

Also, Molar mass of sucrose (C₆H₁₂O₆) = 180 g/mol

So, moles = Given mass/ molar mass

Hence, moles of sucrose in the solution = 10 g / 180 g/mol = 0.05556 mol

Given that: Mass of ethanol = 100 g

Molar mass of ethanol = 46 g/mol

Hence, moles of ethanol = 100 g / 46 g/mol = 2.174 mol

Mole fraction of solvent, ethanol is:

X ethanol = 2.174 mol / (2.174 + 0.05556) mol = 0.975

Applying Raoult's Law

P solution = X ethanol*P° ethanol

<u> => P° ethanol  = P solution / X ethanol  = 55 mmHg / 0.975 = 56.4 mm Hg</u>

6 0
4 years ago
Read 2 more answers
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