The correct answer is 221.06 °C hot.
If P₁ is the pressure at T₁ and P₂ is the pressure at T₂ then,
P₁/T₁ = P₂/T₂
It is given that P₁ = 2.38 atm
T₁ = 15.2 degree C = 273 + 15.2 = 288.2 K
P₂ = 4.08 atm
T₂ = x
Thus, 2.38 / 288.2 = 4.08 / x
x = (4.08 × 288.2) / 2.38
x = 494.06 K
x = 494.06 - 273 °C = 221.06 °C
Therefore, the tire would get 221.06 °C hot.
