The easiest way to find such limits, where there is a numerator and a denominator is to apply <span><span>Hospital's Rule.
1st find the derivative of the numerator and the derivative of the denominator, if it still gives an indeterminate value, find the second derivative of N and D
3) lim sin(2x)/x when x →0
Derivative sin2x → 2cos2x
Derivative x→ 1
2cos2x/1 when x→0 , 2cos2x → 2
and lim sin(2x)/x when x →0 is 2
4) lim(sinx)/(2x²-x)
→cosx/(2x-1) when x →0 cosx/(2x-1) = -1
and lim(sinx)/(2x²-x) when x →0 is -1
and so on and so forth. Try to continue following the same principle
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Answer: Answer is A) Both resulted in US enterprises displacing the control of other colonial powers.
Explanation: I got it correct.
Answer:
The area of parallelogram 1 is 4 square units greater than the area of parallelogram 2.
Explanation:
If you are confused on how to find areas of parallelogram that don't have any parallel sides to the x/y axes, then create a rectangle around the parallelogram and subtract the areas of the triangle from the total area of the rectangle. Example is shown in desmos below:
(Luckily, the first parallelogram happens to be a square so the method above is not necessary)
Area of first parallelogram:
= 20
Area of second parallelogram:
(4*8) - (2*2 + 6*2) = 16
Answer: The area of parallelogram 1 is 4 square units greater than the area of parallelogram 2.